problem number
12.1
12.2
12.3
0
19/70
7/2
2
-4
6
3/2
3
-2
1/2
4
5
5x/2y
L,
12.4 litx
X 1--,)- 5 X _,D.' 6\ -.
01 3
, -8
7
-9 , 2
8
8, -3
9
x/5
)( 3
3( 9- - 0-
E-3b i.\'
0.A-40
5
(ix- y)
3xy2
11
5a219C2
X-
13
xa ( x+-(0)
Sx
8)(x+ 3)
X X—
15
a12°25'-i-vvt-P 11(3*
—1 4
G2 -3 x-y
X-5 x Tk C/
( — 3)( X
f 4)
q 4- (210 17 17
x 1- 1
. 18 19
(
X -51
3 X+5 X') I
'1(
A.
3(
3Y- 4-, )
t
(Y — t))`;'
x (0 -t- t _A__
()(-
3 - X '-)' 4,9 X +9 x. t . X `4(X --AX--5)(x+4)
X -4---
....
ce3 n-) +-,n
(X-t))
nn - fl
( )0-5) 3
Yvi?' n2ern-1-\
)
3 GOA° Li c, V----
ns ( %
Cilli-r)_) . to cl(Gk ) - m 7)1 -3-x — ,y -:-3yyv-k---n D...1. -A
Jr .P.-
(X-clY-x--(X 3x4 x+-5)
' .___-L---
14
16
x-1
x+
1
._ \ -
X / + 1) / (X
(71
a(xus-1
12
-'7(x '
X 4-'‘
s
x°-‘--
X4 a
N4 04 10
(9-
x+y
0,, )0- — _ D., x - 7 X
;....._ 4 x _
i
problem number
12.1
12,2
(
X -3_i X
) 4 k, '2- (X-A)
X-3
(;)
(x-a/i ÷1 ) vx-i-)
3);-:). x-.y,
-6x - 5
1
43
12.3
12.4
(Li x-9)( x 1-)i,N)
-7 x-3 X 4--5
'(.xt5i..)0(
3(x-03 N-4)-5: zx -I
)0-9 cl
1
1/5 [2.2]
(x + 2)(x - 2)
1/8 [6.5]
cA- 6
Co )(.1-3x — 9 3X
m = 4/p [4.4] -.en iArylz_qrlet. 5
26
S'
a(a - 1)
---3-x -f-1
9
0( 4-31.A.--3)
X- LI
xi Lib( cl.--bk0.-13) a (ck -00 '3 (4- 5
9
o 1
3
35
36 37
38 39
g ')(
X =
"+t 5
x 4.-7)
--.4
6( - I Xx -4 4-x-o)
(0 ) --"/5)
-11%-15
X2 -
X--30
X- 3
2
2"
(x4--,
), n
en = 3/5
-I .cv4--6
X—I
0 i:
I
x X
41-
..r...-1i--(7,ro X ts, G1.241c4ntyrr Pi & robr-,,A..utiz,c. (3,04'1 1r '4 --(74— t —)---3--,
(-0-7'-ir71A;'t S ' ' f1(--1?-7:NAA4
44 D C:A.
01 N6:.
6,--cl -% -7/5 [6.7]
120 [10.10]
I ihr, i-,..4-),5 11 ,..-"E c.c.-k1. 6.iy,e4
'5X - 4 Frae-cor, n C* r-e.GiU5+ - 1-77--ii c l, PC rICY) n ot '3 )(
r-faa U. cc( I
roblem l umber
1
12.5
12.6
lax 49 k(s
2
43x/63
d---)--5 7(1 7 1 6 a, -45 i0
9
)( b .
--t O-) '3,-. 3
15 16 17
/ Z 4 riX n 21- 9? "-e i x ,,,sx
19
a -iz1 'a + b
(X—(5)
iiii 3 N. 2- -__:z( 3
-2,6
—ZX
)(+-
+ I) '+
g x - y, X °*4 1 C1`4 1 -1-19 )( -14 4
(x + y)(x - y)
Ca
-7/3, -3
o, 1, -1 x(x + 2)(x + 8)(x + 12)
X
( X -,)-Y.2 „2 x — )1 x - 15
(x - LI X X f-5)
X --.3
(x + 6)(x + 7)(x - 9)
1 4- n--) '2' 1- VY) 3-
4(x - 5)(x + 5)
7 3)( 1- 7 X 4-5 — 2_7( -3
X t- I
6, k i-43
1/4
Y
--1-
( '-0--;1-"IYV5)-
-7x 0- --tDt0x.-k 10 Izx 1-- )(., x +4) ( y.k-- _)- (4 i-3)(-5 18x-132xcx."-vx-k-t-7) .-- )(-00(' 4-3 xi-3 4+ 5 x. - - 9 y -f 17x -,A ___ ,',1,4 - ce ('i< 4-- •)( X -4) CI- - a'( ‘- x - 5)
0(4-1-W( -LA) .-3 ( \k -a) ( 1-5
=-
5 (x-v))
r-hc q -f- Lixdy 1-9x4'1, . - ,o(". _a 3)( - (0 (4, _ rpiA ( x f_44) 3 G73-----i g ic,2 -7,)3. n Li _ T X3 - -F i 3x 56 0 ,t,i x8 x 1 -- 3x `II— 0 10i - -)q — Y '-1 f-- 5-x 6 x f IT
5 x - 5y 1-3 18
-5, 0
x(x
3x .-
01 )('yi f5 2.)(3 5'3-
14
21/5
+ 3y)/15
313
8
13
(2x
1z-
qY1 -3
12
3
3 X 2'
7
11
2/5
3 Co
-7 n,-) 4
10
— 29x163
4xL-)
5 6
Review 12
\Ix --r 5 -7 ( lox -1-___ 4
12.7
— e, - z,25 (01-c-A a1+-5)
a/ X a)-( x 1.--1-1)(x- 17 /Y
(rn + n) 2
x2((x - 4)(x + 4) a)C--,.5
ok 0( 1--,-,1) '1-
3/2
x +- 5 2(x + 3)2
--)c --HP 0( 1-- 6Z7--i--3)
a -3x 3x • ri--6)'
c, ( 3 - 5 ..-pck
(2x + 1)(x + 5)(x - 8)
_ c_" 1
1°),C + I
x- 3 i X -ifif
X-Io 1((x-r3Xx1-5) 'lx 1 X-5 3x -- 1 0 3x -fr 5
mica-A.,J,i be cwoorr) "1751c. .....? Eliminate negative exponent, 3/x2 [3.3]
7x + 5
XL-1 ____
X1-4(
problem Dumber
12.5
12.6
I
12.7
Review 12
x x -8)(3-i3x-4, reimit nes. cieoGm. - " a-'- x MOM= (x1- 4 4e' )(4--8 -3) ---11 5 2 aWo--a/x-.) x 3 +15 )( L -2(ox - 1-1 2 ...a} act.i {--Lth :i- , 2-210 reit“, oaxiicc-k x4-1 -45d• n4-ta EMS (a-b ck A-b x-va (9- - 5 x 4 - a3A4si X(k - btrx - 11 - 3 (x-t x'--. ..-3 y-til X-9Yx-fl y-(1 3(x+ 11)
20
5
21 22
,25 23
)( -y
Lie
x--*/ 24
(Y-3 x- LI
25
x = 2/3 or x = -8/5 [11.2]
Pythagorean theorem [10.6]
26
44 deg, 54 deg, 82 deg [4.2]
zero product property [111]
) ,(77719, -;:„..„.., )0A ' 27
fundamental property of fractions [2.2]
28
distributive property [1.5]
11-6(2- 4 4x. + , )l-t-, Nfx-1- 3 K` a9)(4-1)
4 0 )(
1. )
29
quadratic formula [11.6]
4
30
31
a
32
33
X
34
1 )
3
35
(
36
(
37
(t Y
38
39
)
)
X
)
I-----T
ilEMEZMIll