08 Resolution of Force Problem Set

Report 1 Downloads 69 Views
RESOLUTION OF A FORCE | PRACTICE PROBLEMS Complete the following to reinforce your understanding of the concept covered in this module.

PROBLEM 1: A hurricane wind blowing ๐‘Ž๐‘ก 300 ๐‘š๐‘–๐‘™๐‘’๐‘  ๐‘๐‘’๐‘Ÿ โ„Ž๐‘œ๐‘ข๐‘Ÿ is acting on a building in Sunrise, FL is defined by the force vector ๐น = 3.5๐‘– โˆ’ 1.5๐‘— + 2.0๐‘˜. What is the angle that the force makes with the positive ๐‘ฆ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘ ? A. 20.4ยฐ B. 66.4ยฐ C. 69.6ยฐ D. 110ยฐ

SOLUTION 1: The formula for the RESULTANT OF A THREE-DIMENSIONAL FORCE can be referenced under the topic of STATICS on page 67 of the NCEES Supplied Reference Handbook, 9.4 Version for Computer Based Testing.



Made with

by Prepineer | Prepineer.com

We can calculate the resultant of a three-dimensional force by calculating the magnitude of each component.

๐‘…=

๐‘ฅB + ๐‘ฆB + ๐‘งB =

๐นDB + ๐นEB + ๐นFB

Plugging in the value for each component, we calculate the resultant of the force as:

๐‘…=

3.5

B

+ โˆ’1.5

B

+ 2.0 B = 4.3

We can rewrite the formula for the magnitude of each component by substituting in the formula for the resultant. Therefore, we can solve for the component of each force by using the formula for the resultant of a three-dimensional force:

๐นD =

๐‘ฅ ๐‘ฆ ๐‘ง ๐น; ๐นE = ๐น; ๐นF = ๐น ๐‘… ๐‘… ๐‘…

The formulas for the RESOLUTION OF A FORCE can be referenced under the topic of STATICS on page 67 of the NCEES Supplied Reference Handbook, 9.4 Version for Computer Based Testing. The ๐‘ฆ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘  usually represents the vertical component of the force:

๐นE = cos ๐œƒE ๐‘œ๐‘Ÿ ๐‘๐‘œ๐‘ ๐œƒE =



๐นE ๐น

Made with

by Prepineer | Prepineer.com

As we are solving for the angles the force makes with the positive ๐‘ฆ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘ , we can rewrite the direction cosine for the y-axis to solve for the angle:

๐œƒ = cos NO

๐นE ๐น

Plugging in the given values for the y-component, and the calculated magnitude of the force, we find the angle between the force and the y-axis is:

๐œƒ = cos NO โˆ’

1.5 = 110.4ยฐ 4.3

Therefore, the correct answer choice is D. ๐Ÿ๐Ÿ๐ŸŽยฐ



Made with

by Prepineer | Prepineer.com

PROBLEM 2: A transmission tower is supported by a guy wire that anchored to the ground at point A and attached to the top of the tower at point B. If the cable has a tension of 2,500, what is the resultant of the tensile force closest to:

A. 235,850 B. 243,280 C. 246,800 D. 268,000



Made with

by Prepineer | Prepineer.com

SOLUTION 2: The formula for the RESULTANT OF A THREE-DIMENSIONAL FORCE can be referenced under the topic of STATICS on page 67 of the NCEES Supplied Reference Handbook, 9.4 Version for Computer Based Testing. The line of action of the force acting on the bolt passes through points A and B, and the force is directed from A to B. The components of the vector AB are represented by the distances: ๐‘‘D = โˆ’40 ๐‘š ๐‘‘E = +80 ๐‘š ๐‘‘F = +30 ๐‘š We can write the force for the cable in vector form as: ๐น = 2,500 โˆ’40๐‘– + 80๐‘— + 30๐‘˜ = โˆ’100,000๐‘– + 200,000๐‘— + 75,000๐‘˜ We can calculate the resultant of a three-dimensional force by calculating the magnitude of each component.

๐‘…=

๐‘ฅB + ๐‘ฆB + ๐‘งB

Plugging in the value for each component, we calculate the resultant of the force as:

๐‘…=

โˆ’100,000

B

+ 200,000

B

+ 75,000 B = 235,849.53

Therefore, the correct answer choice is A. ๐Ÿ๐Ÿ‘๐Ÿ“, ๐Ÿ–๐Ÿ“๐ŸŽ

Made with

by Prepineer | Prepineer.com

PROBLEM 3: A force is represented by the force vector ๐น = โˆ’1060๐‘– + 2120๐‘— + 795๐‘˜, what is the angle that the force makes with the positive ๐‘ฅ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘ ? A. 20.4ยฐ B. 32.0ยฐ C. 71.5ยฐ D. 115.1ยฐ

SOLUTION 3: The formula for the RESULTANT OF A THREE-DIMENSIONAL FORCE can be referenced under the topic of STATICS on page 67 of the NCEES Supplied Reference Handbook, 9.4 Version for Computer Based Testing. We can calculate the resultant of a three-dimensional force by calculating the magnitude of each component.

๐‘…=

๐‘ฅB + ๐‘ฆB + ๐‘งB =

๐นDB + ๐นEB + ๐นFB

Plugging in the value for each component, we calculate the resultant of the force as:

๐‘…=



1060

B

+ 2120

B

+ 795 B = 2500

Made with

by Prepineer | Prepineer.com

We can rewrite the formula for the magnitude of each component by substituting in the formula for the resultant. Therefore, we can solve for the component of each force by using the formula for the resultant of a three-dimensional force:

๐นD =

๐‘ฅ ๐‘ฆ ๐‘ง ๐น; ๐นE = ๐น; ๐นF = ๐น ๐‘… ๐‘… ๐‘…

The formulas for the RESOLUTION OF A FORCE can be referenced under the topic of STATICS on page 67 of the NCEES Supplied Reference Handbook, 9.4 Version for Computer Based Testing. The ๐‘ฅ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘  usually represents the horizontal component of the force:

๐นD = cos ๐œƒD ๐‘œ๐‘Ÿ ๐‘๐‘œ๐‘ ๐œƒD =

๐นD ๐น

As we are solving for the angles the force makes with the positive ๐‘ฅ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘ , we can rewrite the direction cosine for the x-axis to solve for the angle:

๐œƒ = cos NO

๐นD ๐น

Plugging in the given values for the x-component, and the calculated magnitude of the force, we find the angle between the force and the ๐‘ฅ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘  is:

๐œƒ = cos NO โˆ’



1060 = 115.1ยฐ 2500

Made with

by Prepineer | Prepineer.com

Therefore, the correct answer choice is D. ๐Ÿ๐Ÿ๐Ÿ“. ๐Ÿยฐ PROBLEM 4: A force is represented by the force vector ๐น = โˆ’1060๐‘– + 2120๐‘— + 795๐‘˜, what is the angle that the force makes with the positive ๐‘ฆ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘ ? A. 20.4ยฐ B. 32.0ยฐ C. 71.5 D. 115.1ยฐ

SOLUTION 4: The FORMULA FOR THE RESULTANT OF A THREE-DIMENSIONAL FORCE can be referenced under the topic of STATICS on page 67 of the NCEES Supplied Reference Handbook, 9.4 Version for Computer Based Testing. We can calculate the resultant of a three-dimensional force by calculating the magnitude of each component.

๐‘…=



๐‘ฅB + ๐‘ฆB + ๐‘งB =

๐นDB + ๐นEB + ๐นFB

Made with

by Prepineer | Prepineer.com

Plugging in the value for each component, we calculate the resultant of the force as:

๐‘…=

1060

B

+ 2120

B

+ 795 B = 2500

We can rewrite the formula for the magnitude of each component by substituting in the formula for the resultant. Therefore, we can solve for the component of each force by using the formula for the resultant of a three-dimensional force:

๐นD =

๐‘ฅ ๐‘ฆ ๐‘ง ๐น; ๐นE = ๐น; ๐นF = ๐น ๐‘… ๐‘… ๐‘…

The formulas for the RESOLUTION OF A FORCE can be referenced under the topic of STATICS on page 67 of the NCEES Supplied Reference Handbook, 9.4 Version for Computer Based Testing. The ๐‘ฆ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘  usually represents the vertical component of the force:

๐นE = cos ๐œƒE ๐‘œ๐‘Ÿ ๐‘๐‘œ๐‘ ๐œƒE =

๐นE ๐น

As we are solving for the angles the force makes with the positive ๐‘ฆ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘ , we can rewrite the direction cosine for the ๐‘ฆ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘  to solve for the angle:

๐œƒ = cos NO



๐นE ๐น

Made with

by Prepineer | Prepineer.com

Plugging in the given values for the y-component, and the calculated magnitude of the force, we find the angle between the force and the ๐‘ฆ โˆ’ ๐‘Ž๐‘ฅ๐‘–๐‘  is:

๐œƒ = cos NO

2120 = 32.0ยฐ 2500

Therefore, the correct answer choice is B. ๐Ÿ‘๐Ÿ. ๐ŸŽยฐ

PROBLEM 5: A particle is in equilibrium is said to be in three-dimensional static equilibrium with 10 forces acting on it. How many equations of equilibrium can be written for the particle? A. 2 B. 3 C. 4 D. ๐‘๐‘œ๐‘›๐‘’ ๐‘œ๐‘“ ๐‘กโ„Ž๐‘’ ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’

SOLUTION 5: When working with problems in three-dimensions, we can only sum the forces around each axis that a force or forces is acting about. Therefore, as we have 3 dimensions or plans of equilibrium, the maximum amount of equilibrium equations we can write is three (x, y, and z).

Therefore, the correct answer choice is B. ๐Ÿ‘

Made with

by Prepineer | Prepineer.com

PROBLEM 6: A particle is in equilibrium is said to be in three-dimensional static equilibrium with no external forces acting on it. Which of the following equations would represent the static equilibrium of the particle? A. โˆ‘๐นD ๐‘– + โˆ‘๐นE ๐‘— + โˆ‘๐นF ๐‘˜ = 0 B. โˆ‘๐น = 0 C. โˆ‘๐นD = โˆ‘๐นE = โˆ‘๐นF = 0 D. ๐ด๐‘™๐‘™ ๐‘œ๐‘“ ๐‘กโ„Ž๐‘’ ๐‘Ž๐‘๐‘œ๐‘ฃ๐‘’

SOLUTION 6: When working with problems in three-dimensions, we can only sum the forces around each axis that a force or forces is acting about. Therefore, as we have 3 dimensions or plans of equilibrium, the maximum amount of equilibrium equations we can write is three (x, y, and z). As we are told that the particle is in static equilibrium, we know that the sum of forces about any plane or axis will be equal to zero. Looking at the answer choices, we see that all three are different forms of expressing the equations of equilibrium of 3-D particle in static equilibrium.

Therefore, the correct answer choice is D. ๐‘จ๐’๐’ ๐’๐’‡ ๐’•๐’‰๐’† ๐’‚๐’ƒ๐’๐’—๐’†



Made with

by Prepineer | Prepineer.com

PROBLEM 7: When working with three-dimensional problems and you are not given the direction or the magnitude of a force, how many unknowns do you have corresponding to that force? A. ๐‘‚๐‘›๐‘’ B. ๐‘‡๐‘ค๐‘œ C. ๐‘‡โ„Ž๐‘Ÿ๐‘’๐‘’ D. ๐น๐‘œ๐‘ข๐‘Ÿ

SOLUTION 7: When working with problems in three-dimensions, we can only sum the forces around each axis that a force or forces is acting about. Therefore, as we have 3 dimensions or plans of equilibrium, the maximum amount of equilibrium equations we can write is three (x, y, and z). As we have three dimensions and do not have the magnitude of the force, we will have three components of the force that we will need to solve for.

Therefore, the correct answer choice is C. ๐‘ป๐’‰๐’“๐’†๐’†



Made with

by Prepineer | Prepineer.com