11. Polar Coordinate System Concept Overview

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POLAR COORDINATE SYSTEM | CONCEPT OVERVIEW The topic of POLAR COORDINATE SYSTEMS can be referenced on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing.

CONCEPT INTRO: The Cartesian Coordinate System, is a RECTANGULAR COORDINATE SYSTEM, where β€œπ‘₯” and β€œπ‘¦β€ represent the directed distances from the coordinates axes to the point (π‘₯, 𝑦).

The rectangular coordinates are a measure of how far away a point is from a reference axis: β€’ The x-coordinate β€œπ‘₯” is the directed distance from the y-axis to the point of reference β€’ The y-coordinate β€œπ‘¦β€ is the directed distance from the x-axis to the point of reference.



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In the POLAR COORDINATE SYSTEM, polar coordinates (π‘Ÿ, πœƒ) are determined by a distance (π‘Ÿ) and angle πœƒ , that measures the angle between the positive π‘₯– π‘Žπ‘₯𝑖s and a ray that goes through the point. You can think of a polar coordinate system as how far away a coordinate is, and what it is relative to the origin.

To form the polar coordinate system in the plane, we determine the POLE or ORIGIN, and construct a RAY or line that is oriented relative to the POLAR AXIS. At the end of this line we find a point that has the coordinates (π‘Ÿ, πœƒ). We

can

convert

between

POLAR

COORDINATES

and

RECTANGULAR

COORDINATES by using known geometric relationships such as the Pythagorean theorem.



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The distance or ray β€œπ‘Ÿβ€ represents the hypotenuse in the Pythagorean theorem, and helps us to relate the vertical and horizontal components as demonstrated in the figure above. The

FORMULAS

TO

CONVERT

BETWEEN

POLAR

AND

RECTANGULAR

COORDINATES can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing.

The β€œπ‘₯” and β€œπ‘¦β€ coordinates of the RECTANGULAR FORM can be determined from the radius π‘Ÿ and angle (πœƒ) using the formulas: π‘₯ = π‘Ÿ cos πœƒ

𝑦 = π‘Ÿ sin πœƒ

tan πœƒ =

4 5

Where: β€’ π‘Ÿ is the distance from the origin to the point

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β€’ π‘₯ is the x-coordinate of the rectangular coordinates β€’ 𝑦 is the y-coordinate of the rectangular coordinates β€’ πœƒ is the angle between the ray "π‘Ÿβ€ and the positive π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠 The FORMULA FOR THE POLAR FORM A COMPLEX NUMBER can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. The polar form of a nonzero complex number is represented by the expression: 𝑧 = π‘₯ + 𝑗𝑦 = π‘Ÿ(cos πœƒ + 𝑗 sin πœƒ) = π‘Ÿπ‘’ => Where: β€’ π‘Ÿ is the modulus of the complex number β€’ πœƒ is the argument of the complex number

The radius and angle of the polar form of the nonzero complex number can be determined from the β€œπ‘₯” and β€œπ‘¦β€ coordinates using the formulas:

π‘Ÿ = π‘₯ + 𝑗𝑦 = πœƒ = arctan

π‘₯? + 𝑦?

4 5

Where: β€’ π‘Ÿ is the distance from the origin to the point

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β€’ π‘₯ is the x-coordinate of the rectangular coordinates β€’ 𝑦 is the y-coordinate of the rectangular coordinates β€’ πœƒ is the angle between the ray β€œπ‘Ÿβ€ and the positive π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠 The FORMULAS AND VARIOUS FORMS OF EULER’S IDENTITY can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. EULER’S IDENTITY is used to express a complex number as related the trigonometric functions cosine and sine, which represents a power series of the function. 𝑒 => = cos πœƒ + 𝑗 sin πœƒ 𝑒 A=> = cos πœƒ βˆ’ 𝑗 sin πœƒ

Using’s Euler’s Identity, we can rewrite exponential terms in terms of trigonometric functions, or to rewrite trigonometric functions in terms of exponential terms. 𝑒 => + 𝑒 A=> cos πœƒ = 2 𝑒 => βˆ’ 𝑒 A=> sin πœƒ = 2𝑗



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CONCEPT EXAMPLE: The following problem introduces the concept reviewed within this module. Use this content as a primer for the subsequent material.

What is the rectangular form of the following polar equation: π‘Ÿ ? = 1 βˆ’ tan? πœƒ A. βˆ’π‘₯ ? + π‘₯ D 𝑦 ? + 𝑦 ? = 0 B. π‘₯ ? + π‘₯ ? 𝑦 ? βˆ’ 𝑦 ? + 𝑦 D = 0 C. βˆ’π‘₯ D + 𝑦 ? = 0 D. π‘₯ D βˆ’ π‘₯ ? + π‘₯ ? 𝑦 ? + 𝑦 ? = 0

SOLUTION: The

FORMULAS

TO

CONVERT

BETWEEN

POLAR

AND

RECTANGULAR

COORDINATES can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. The radius and angle of the POLAR FORM can be determined from the β€œπ‘₯” and β€œπ‘¦β€ coordinates using the formulas:

π‘Ÿ = π‘₯ + 𝑗𝑦 =

π‘₯? + 𝑦? Made with

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πœƒ = arctan

4 5

Where: β€’ π‘Ÿ is the distance from the origin to the point β€’ π‘₯ is the x-coordiante of the rectangular coordinates β€’ 𝑦 is the y-coordinate of the rectangular coordinates β€’ πœƒ is the angle between the ray β€œπ‘Ÿβ€ and the positive π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠 Plugging in the values from the given complex expression, we find: π‘Ÿ ? = 1 βˆ’ tan πœƒ ? We can re-write the radius squared as a function of β€œπ‘₯” and β€œπ‘¦β€ coordinates to help us get both sides of the equation to have like terms:

π‘Ÿ = π‘₯ + 𝑗𝑦 =

π‘₯? + 𝑦?

?

π‘₯? + 𝑦?

= 1 βˆ’ tan? πœƒ

We can then replace the angle πœƒ with the trigonometric expression that relates the angle to the β€œπ‘₯” and β€œπ‘¦β€ coordinates to help us get both sides of the equation to have like terms:

πœƒ = arctan π‘₯? + 𝑦?

4 5 ?

= 1 βˆ’ tan? tanAF Made with

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Simplifying our expression, we find:

π‘₯? + 𝑦? = 1 βˆ’

4G 5G

Therefore, the correct answer choice is D. π’™πŸ + π’šπŸ = 𝟏 βˆ’

π’šπŸ π’™πŸ

MULTIPLICATION AND DIVISION OF COMPLEX NUMBERS IN POLAR FORM: The multiplication and division rules defined for complex numbers expressed in rectangular form can be applied to complex number expressed in polar form. The FORMULA TO CALCULATE THE PRODUCT OF TWO COMPLEX NUMBER IN POLAR REPRESENTATION can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing.

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Using trigonometric identities, we calculate the product of complex numbers in polar form as: [π‘ŸF (cos πœƒF + 𝑗 sin πœƒF )][π‘Ÿ? (cos πœƒ? + 𝑗 sin πœƒ? )] = π‘ŸF π‘Ÿ? [cos πœƒF + πœƒ? + 𝑗 sin(πœƒF + πœƒ? )] The FORMULA TO CALCULATE THE QUOTIENT OF TWO COMPLEX NUMBER IN POLAR REPRESENTATION can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. The quotient of complex numbers in polar form is expressed as: π‘ŸF (cos πœƒF + 𝑗 sin πœƒF ) π‘ŸF = cos πœƒF βˆ’ πœƒ? + 𝑗 sin(πœƒF βˆ’ πœƒ? ) π‘Ÿ? (cos πœƒ? + 𝑗 sin πœƒ? ) π‘Ÿ?

Where: β€’ π‘Ÿ is the absolute value of modulus of the complex number β€’ π‘₯ is the x-coordinate of the rectangular coordinates β€’ 𝑦 is the y-coordinate of the rectangular coordinates β€’ πœƒ is the angle between the ray "π‘Ÿβ€ and the positive π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠

CONCEPT EXAMPLE: The following problem introduces the concept reviewed within this module. Use this content as a primer for the subsequent material.

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What is the quotient of following complex numbers in polar representation? 𝑧F = 2(cos 120Β° + 𝑗 sin 120Β°) 𝑧? = 3(cos 30Β° + 𝑗 sin 30Β°) A.

?

B.

?

C.

?

D.

?

P P P P

cos 90Β° βˆ’ 𝑗 sin 90Β° cos 90Β° + 𝑗 sin 90Β° sin 90Β° βˆ’ 𝑗 cos 90Β° sin 90Β° + 𝑗 cos 90Β°

SOLUTION: We are given the two complex numbers in polar form: 𝑧F = 2(cos 120Β° + 𝑗 sin 120Β°) 𝑧? = 3(cos 30Β° + 𝑗 sin 30Β°) The FORMULA TO CALCULATE THE QUOTIENT OF TWO COMPLEX NUMBER IN POLAR REPRESENTATION can be referenced under the topic of MATHEMATICS on



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page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. We can calculate the quotient of two complex numbers in polar representation

using

the formula: π‘ŸF (cos πœƒF + 𝑗 sin πœƒF ) π‘ŸF = cos πœƒF βˆ’ πœƒ? + 𝑗 sin(πœƒF βˆ’ πœƒ? ) π‘Ÿ? (cos πœƒ? + 𝑗 sin πœƒ? ) π‘Ÿ? Where: β€’ π‘Ÿ is the absolute value of modulus of the complex number β€’ π‘₯ is the x-coordinate of the rectangular coordinates β€’ 𝑦 is the y-coordinate of the rectangular coordinates β€’ πœƒ is the angle between the ray "π‘Ÿβ€ and the positive π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠

Plugging in the given complex expressions, we find the quotient of the two complex numbers is expressed as: 𝑧F 2(cos 120Β° + 𝑗 sin 120Β°) = 𝑧? 3(cos 30Β° + 𝑗 sin 30Β°) We can simplify this expression using the formula to find the quotient of two complex numbers in polar representation:



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π‘ŸF (cos πœƒF + 𝑗 sin πœƒF ) π‘ŸF = cos πœƒF βˆ’ πœƒ? + 𝑗 sin(πœƒF βˆ’ πœƒ? ) π‘Ÿ? (cos πœƒ? + 𝑗 sin πœƒ? ) π‘Ÿ? Where: β€’ π‘Ÿ is the absolute value of modulus of the complex number β€’ π‘₯ is the x-coordinate of the rectangular coordinates β€’ 𝑦 is the y-coordinate of the rectangular coordinates β€’ πœƒ is the angle between the ray "π‘Ÿβ€ and the positive π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠 We find the variable has the values of: β€’ π‘ŸF = 2 β€’ π‘Ÿ? = 3 β€’ πœƒF = 120Β° β€’ πœƒ? = 30Β°

Plugging in the values from the given complex expressions, we find the quotient of the two complex numbers is expressed as: 𝑧F 2 = cos 120Β° βˆ’ 30Β° + 𝑗 sin(120Β° βˆ’ 30Β°) 𝑧? 3 Simplifying our expression, we find:



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𝑧F 2 = (cos 90Β° + 𝑗 sin 90Β°) 𝑧? 3 𝟐

Therefore, the correct answer choice is B. (𝐜𝐨𝐬 πŸ—πŸŽΒ° + 𝐣 𝐬𝐒𝐧 πŸ—πŸŽΒ°) πŸ‘

DE MOIVRE’S FORMULA: The TOPIC OF DE MOIVRE’S FORMULA can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. DE MOIVRE’S THEOREM is used to calculate power and roots of complex numbers given in polar form. The FORMULA FOR DE MOIVRE’S THEOREM can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. DE MOIVRE’S FORMULA is used to relate complex numbers and trigonometry. We can use De Moivre’s Formula to find the powers of complex numbers in complex form. 𝑧 = π‘₯ + 𝑗𝑦

[

= [π‘Ÿ(cos πœƒ + jsin πœƒ)][ = π‘Ÿ [ (cos π‘›πœƒ + 𝑗 sin π‘›πœƒ)

Where: β€’ 𝑛 is a positive integer



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We commonly use the following notation when working with complex number in polar form: π‘Ÿβˆ πœƒ = π‘Ÿ cos πœƒ + 𝑗 sin πœƒ

[

In order to find the nth power of a complex number, we need to take the nth power of the absolute value or length and multiply the argument by β€œπ‘Ÿβ€. The FORMULA FOR THE ROOTS OF A COMPLEX NUMBER can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. The kth root, β€œπ‘€β€, of a complex number is found from the equation expressed as: The β€œπ‘˜β€ roots of π‘Ÿ(cos πœƒ + 𝑗 sin πœƒ) can be found by substituting successively 𝑛 = 0,1,2, … (π‘˜ βˆ’ 1) in the formula:

𝑀=

b

π‘Ÿ cos

πœƒ 360Β° πœƒ 360Β° + 𝑛 + 𝑗 sin + 𝑛 π‘˜ π‘˜ π‘˜ π‘˜

If β€œπ‘˜β€ is any positive integer, any complex number (other than zero), has β€œπ‘˜β€ distinct roots. >

The amplitude of the first root, w is calculated as 𝑀F = . The point representing the d

roots 𝑀F , 𝑀? , … , 𝑀d are equal spaced on a unit circuits with a radius of the origin. The difference between each root on a unit circle can be calculated as:

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b

π‘Ÿ drawn about

π›₯Β° =

360Β° π‘˜

CONCEPT EXAMPLE: The following problem introduces the concept reviewed within this module. Use this content as a primer for the subsequent material.

Find βˆ’1 + 3𝑗

F?

and write the result in standard form.

A. 3096 B. 4096 C. 5096 D. 6096

SOLUTION: The FORMULA FOR THE POLAR FORM A COMPLEX NUMBER can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. The first step is to convert the complex expression to polar form to match the standard expression for polar form of nonzero complex number: 𝑧 = βˆ’1 + 3𝑗 The polar form of a nonzero complex number is represented by the expression:

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𝑧 = π‘₯ + 𝑗𝑦 = π‘Ÿ(cos πœƒ + 𝑗 sin πœƒ) = π‘Ÿπ‘’ => Where: β€’ π‘Ÿ is the modulus of the complex number β€’ πœƒ is the argument of the complex number The radius and angle of the polar form of the nonzero complex number can be determined from the β€œπ‘₯” and β€œπ‘¦β€ coordinates using the formulas:

π‘Ÿ = π‘₯ + 𝑗𝑦 = πœƒ = arctan

π‘₯? + 𝑦?

4 5

Where: β€’ π‘Ÿ is the distance from the origin to the point β€’ π‘₯ is the x-coordinate of the rectangular coordinates β€’ 𝑦 is the y-coordinate of the rectangular coordinates β€’ πœƒ is the angle between the ray β€œπ‘Ÿβ€ and the positive π‘₯ βˆ’ π‘Žπ‘₯𝑖𝑠 Plugging in the values from the given expression, we can solve for modulus and argument of the complex number:

π‘Ÿ = π‘₯ + 𝑗𝑦 =

π‘₯? + 𝑦?

π‘Ÿ = βˆ’1 + 𝑗 3 =



(βˆ’1)? +

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πœƒ = arctan

tan πœƒ =

𝑦 π‘₯

𝑦 3 = =βˆ’ 3 π‘₯ βˆ’1

πœƒ = arctan βˆ’ 3 =

2πœ‹ 3

We then final polar form of the complex number can be re-written as: 𝑧 = π‘₯ + 𝑗𝑦 = π‘Ÿ(cos πœƒ + 𝑗 sin πœƒ) = π‘Ÿπ‘’ =>

𝑧 = βˆ’1 + 3𝑗 = 2 cos

2Ο€ 2πœ‹ +𝑗 sin 3 3

The FORMULA FOR DE MOIVRE’S THEOREM can be referenced under the topic of MATHEMATICS on page 23 of the NCEES Supplied Reference Handbook, Version 9.4 for Computer Based Testing. Using De Movire’s Theorem, we can expand the complex expression, such that we can then simplify it in the next step: 𝑧 = π‘₯ + 𝑗𝑦

[

= [π‘Ÿ(cos πœƒ + jsin πœƒ)][ = π‘Ÿ [ (cos π‘›πœƒ + 𝑗 sin π‘›πœƒ)

𝑧 = βˆ’1 + 3𝑗



F?

2πœ‹ 2πœ‹ = 2 cos + 𝑗 sin 3 3

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𝑧 = 2F? cos

12 2πœ‹ 12 2πœ‹ + 𝑗 sin 3 3

Simplifying we find the can simplifying the complex express to it’s final form: 𝑧 = 4096(cos 8πœ‹ + 𝑗 sin 8πœ‹) = 4096 1 + 𝑖 0

= 4096

Therefore, the correct answer choice is B. πŸ’πŸŽπŸ—πŸ”



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