CHM138H1 Jasmyn Lee 1 Chapter 8: Alkenes ...

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Chapter 8: Alkenes: Reactions and Synthesis

CHM138H1 Jasmyn Lee

(Not Simmons-Smith reactions or epoxidations, not 8.10 or 8.11) Topics:  Synthesis via elimination reactions  Halogenation and halohydrin formation  Addition of water to alkenes (oxymercuration, hydroboration-oxidation)  Carbene reactions (:CCL2)  Hydrogenation (H2/cat.)  Dihydroxylation (OsO4), diol cleavage with IO4 Ozonolysis  Stereochemistry of alkene addition

8.1 Preparing Alkenes: A Preview of Elimination Reactions Synthesis of Alkenes via Elimination Reactions:  Base Elimination



Acid-Catalyzed Elimination



Dehydrohalogenation – the loss of HX from an alkyl halide o Usually occurs by reaction of an alkyl halide with strong base (eg/ KOH) Dehydration – the loss of water from an alcohol o Often carried out by treatment of an alcohol with a strong acid



Quick Review: Addition of HX (X=CL, Br, I) to Alkenes

 

The reaction goes through the more stable carbocation When both carbocations have similar stability:

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8.2 Halogenation of Alkenes: Addition of X2

CHM138H1 Jasmyn Lee

From H-X Addition

 

By this mechanism, should see 50:50 mixture of cis and trans In reality, only the trans isomer is observed



Reaction occurs with anti stereochemistry – atoms add from opposite faces of the double bond o Bromonium ion (R2Br+) is formed as an intermediate

 

Bromonium ion “shields” one face of ring – only the opposite face is available ANTI addition

8.3 Halohydrins from Alkenes: Addition of HOX Halohydrin Formation  Reaction of alkenes with the hypohalous acids HO-Cl or HO-Br to yield 1,2-halo alcohols (halohydrins)  Halohydrin formation does not take place by direct reaction of an alkene with HOBr or HO Cl o Addition is done indirectly by reaction of the alkene with either Br2 or Cl2 in the presence of water  Recall: When Br2 reacts with an alkene, the cyclic bromonium ion intermediate reacts with the only nucleophile present, Br- ion  If the reaction is carried out in the presence of an additional nucleophile, the intermediate bromonium ion can be intercepted by the added nucleophile and diverted to a different product o In the presence of high concentration of H2O – water competes with Br- ion as nucleophile and reacts with the bromonium ion intermediate to yield a bromohydrin

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o

Net Effect – addition of HO-Br to the alkene

CHM138H1 Jasmyn Lee

Halohydrin Formation (2)

Bromohydrin Formation with NBS  Few alkenes are soluble in water – bromoydrin formation is often carried out in solvent CH3SOCH3 (DMSO)  NBS – source of Br2, stable, easily handled compound that slowly decomposes in water to yield Br2 at a controlled rate  NBS reacts slowly with water to produce a low constant level of Br2  This is a safer way of running this reaction; note, ring doesn’t react

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CHM138H1 Jasmyn Lee

Hydration of Alkenes: 8.4 Addition of H2O by Oxymercuration/ 8.5 Addition of H2O by Hydroboration  Hydration – H2O adds to alkenes to yield alcohols o Strong acid catalyst (eg/ H2SO4)  In Industry:



In Living Cells

Electrophilic Addition Reactions Review

Hydration Reactions in the Lab Oxymercuration  Involves electrophilic addition of Hg2+ to the alkene on reaction with mercury (II) acetate, (CH3CO2)2Hg (abbrv. Hg(OAC)2) in aqueous THF solvent

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   

CHM138H1 Jasmyn Lee

Initiated by electrophilic addition of Hg2+ (mercuric) ion to the alkene  Gives a mercurinium ion Nucleophilic addition of water and loss of a proton  Yields a stable organomercury product Demercuration of the organomercury compound by reaction with sodium borohydride Note – Markovnikov addition of water

Hydroboration  Addition of B-H bond of borane, BH3, to an alkene to yield an organoborane intermediate, RBH2  Oxidation of the organoborane by reaction with basic hydrogen peroxide, H2O2, gives an alcohol



Borane is a good electrophile with an empty p-orbital o Borane is very reactive as a Lewis Acid – boron atom has only 6 valence electrons; BH3 accepts an electron pair form a solvent molecule to complete its octet



Syn Stereochemistry o Boron and hydrogen add to the alkene from the same face of the double bond – boron attaches to the less highly substituted carbon o Curing the oxidation step, the boron is replaced by an –OH with the same stereochemistry – resulting in an overall syn non-Markovnikov addition of water o Occurs in a single step without a carbocation intermediate – because both C-H and C-B bonds form at the same time and from the same face of the alkene, syn stereochemistry results o Non Markovnikov regiochemistry occurs – because attachment of boron is favoured at the less sterically crowded carbon atom of the alkene

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CHM138H1 Jasmyn Lee

8.6 Reduction of Alkenes: Hydrogenation  Hydrogenation – alkenes react with H2 in the presence of a metal catalyst (palladium or platinum) to yield a saturated addition product  Reduction o General Chemistry – the gain of one or more electrons by an atom o Organic Chemistry – a reaction that results in a gain of electron density by carbon, caused by either a bond formation between C and a less EN atom eg/ H), or by a bond breaking between C and a more EN atom (eg/ O, N, X)  Addition of H2 gas to alkenes gives alkanes (or cycloalkanes)

  

Homogeneous Process – hydrogenation reaction occurs o the surface of solid catalyst particles SYN addition – both H atoms add to the same face of alkenes Catalyst: often Pd/C or PtO2 (Adam’s Catalyst)  Adsorption of H2 onto catalyst surface  Complexation between catalyst and alkene – a vacant orbital on the metal interacts with the filled alkene  orbital  Hydrogen is inserted into the double bond  The saturated product diffuses away from the catalyst  The stereochemistry of hydrogenation is syn because both hydrogen’s add to the double bond from the same catalyst surface

 

The double bond is hydrogenated or reduced by the addition of H2 Other multiple bonds are usually unaffected by these conditions o Alkenes are more reactive than other unsaturated functional groups o Aldehydes, ketones, esters and nitriles often are unaffected by hydrogenation

8.7 Oxidation of Alkenes: Epoxidation and Hydroxylation  Oxidation o General Chemistry – the loss of one or more electrons b tab atom o Organic Chemistry – a reaction that results in a loss of electron density by C, caused by either a bond formation between C and a more EN atom (O, N, X), or by a bond breaking between C and a less EN atom (H) o Often adds oxygen (vs. reduction – adds hydrogen)

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CHM138H1 Jasmyn Lee

Epoxidation  Alkenes are oxidized to give epoxides on treatment with peroxyacid, RCO3H  Epoxide (oxarane) – a cyclic ether with an oxygen atom on a three-membered ring  Peroxyacids – transfer an oxygen atom to the alkene with syn stereochemistry – both C-O bonds form on the same face of the double bond (one step mechanism; no intermediates)  Oxygen atom farthest from carbonyl group is the one transferred  Epoxides can be synthesized through the use of halohydrins o Electrophilic addition of HO-X to alkenes to synthesize epoxides (8.3) o When a halohydrin is treated with base, HX is eliminated and an epoxide is produced

Hydrolysis  Epoxides undergo an acid-catalyzed ring-opening reaction with water to give the corresponding 1,2-dialcohol, or diol/glycol Hydroxylation  Net result of the two step alkene epoxidation/hydrolysis o The addition of an –OH group to each of the two double bond carbons o Acid-catalyzed epoxide opening takes place by protonation of the epoxide to increase its reactivity, followed by Nucleophilic addition of water  Hydroxylation carried out directly without going through an intermediate epoxide – treat an alkene with osmium tetraoxide, OsO4 o Occurs with syn stereochemistry o No carbocation intermediate o Cyclic osmate intermediate – formed in a single step by addition of OsO4 to the alkene o Cyclic osmate intermediate is them cleaved using aqueous sodium bisulphide, NaHSO3 Dihydroxylation

8.8 Oxidation of Alkenes: Cleavage to Carbonyl Compounds  Powerful oxidizing reagents cleave C=C bonds and produce two carbonyl-containing fragments o As opposed to converting C=C bonds to C-C bonds without changing the C skeleton Alkene Cleavage  C=C bonds can be completely broken  Two methods: o Diol formation, followed by cleavage with HIO4 o Ozonolysis (using ozone, O3) o Permanganate Oxidation (using KMnO4, H+)  Products are C=O containing compounds

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CHM138H1 Jasmyn Lee Diol Cleavage with Periodic Acid, IO4 Two step process; initial hydroxylation to a 1,2-diol, then treatment with periodic acid  If the two –OH groups are in an open chain – two carbonyl compounds result  If the two –OH groups are on a ring - a single, open chain carbonyl compound is formed Ozonolysis – direct cleavage  Ozone (O3)  Passing a stream of oxygen through a high-voltage electrical discharge – ozone adds rapidly to a C=C bond at low temperature to give a cyclic intermediate, molozonide  Molozonide spontaneously rearranges to form an ozonide  Ozonide is immediately treated with a reducing agent (eg/ zinc meta in acetic acid) to convert it to carbonyl compounds  Net Result: C=C bond is cleaved and an oxygen atom becomes double bonded to each of the original alkene carbons o Alkene with tetrasubstituted double bond is ozonized – two ketone fragments result o Alkene with trisubstituted double bond is ozonized – one ketone, one aldehyde

(Typical Q)

Permanganate – direct cleavage  Not as frequently used as ozone  Potassium Permanganate, KMnO4, in neutral or acidic solution cleaves alkenes to give carbonyl-containing products  If hydrogen’s are present on the double bond, carboxylic acids are produced  If two hydrogen’s are present on one carbon, CO2 is formed

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CHM138H1 Jasmyn Lee 8.9 Addition of Carbenes to Alkenes: Cyclopropane Synthesis  Carbene = R2C: o Neutral, 6 electrons in valence shell, VERY reactive o Generated only as a reaction intermediate rather than an insoluble molecule o Behave as electrophiles (electron deficient) – react with nucleophile C=C bonds

Reaction: single step, no intermediates

Dichlorocarbene  Generating a substituted carbine – treat chloroform, CHCl3, with a strong base (eg/ KOH)  CHCl3 (chloroform) loses a proton  - :CCl3 (trichloromethanide anion)  - :CCl3 expels a Cl- ion  :CCl2 (dichlorocarbene) 

The dichlorocarbene C atom is sp2 hybridized – vacant p orbital extending above and below the plane of the three atoms and an unshared pair of electrons occupying the third sp2 lobe

8.12 Reaction Stereochemistry: Addition of H2O HBr to an Achiral Alkene Creates a racemic mixture because:  1-Butene is protonated  intermediate 2 carbocation  Trivalent C is sp2 hybridized and planar – the cation has a plane of symmetry and is achiral  It can react from either top or bottom  Top Rxn – (S)-2-bromobutane through transition state 1  Bottom Rxn – (R)-2-bromobutane through transition state 2







TS1 and TS2 are mirror images o Have identical energies o Form at identical rates o Are equally likely to occur Optically inactive racemic mixture

Formation of a new chirality center by reaction of achiral reactants always leads to a racemic mixture of enantiomer products

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CHM138H1 Jasmyn Lee

An optically active product can only result by starting with an optically active reactant or chiral environment Addition of Br2 o



8.13 Reaction Stereochemistry: Addition of HBr to Chiral Alkene 







Configuration at C4 (CH3 bearing C) o R configuration in starting material, chirality center is unaffected by the reaction o Configuration is unchanged Configuration at C2 (newly formed chirality center, Br bearing C) o The stereochemistry is established by reaction of HBr with a carbocation intermediate o Carbocation does not have a plane of symmetry and is chiral o Does not react equally well on both top and bottom o Mixture of two diastereomeric products Optically active

The formation of a new chirality center by the reaction of a chiral reactant leads to unequal amounts of diastereomic products o If the chiral reactant is optically active because only one enantiomer is used rather than a racemic mixture, then the products are also optically active

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