Date Quiz 8-1 Acids and Bases pH

Name __________________________________________________ Period ________ Date ______________________ Quiz 8-1 Acids and Bases pH – Version 10

Total Points: _______/10

1. (a) Name the acid H2SO4. Sulfuric acid

(½ pt)

(b) Write the balanced dissociation equation for H2SO4 in an aqueous solution. 𝐻2 𝑆𝑂4 (𝑎𝑞) → 2 𝐻 + (𝑎𝑞) + 𝑆𝑂42− (𝑎𝑞) (c) Determine the [H+] in 0.0350 M H2SO4.

(½ pt)

Answer (½ pt)

Show Work (1/4 pt)

Sigfigs (1/4 pt)

(d) Calculate the pH of 0.00350 M H2SO4. 𝑝𝐻 = −𝑙𝑜𝑔[𝐻 + ] = −𝑙𝑜𝑔(0.0700) = 1.155

Answer (½ pt)

Work (1/4)

SF (1/4)

(e) Calculate the pOH of 0.0350 M H2SO4. 𝑝𝐻 + 𝑝𝑂𝐻 = 14.00

Answer (½ pt)

Work (1/4)

SF (1/4)

Answer (½ pt)

Work (1/4)

SF (1/4 pt)

𝐻2 𝑆𝑂4 (𝑎𝑞) → 2 𝐻 + (𝑎𝑞) + 𝑆𝑂42− (𝑎𝑞) 0.0350 M 0.0700 M 0.0350 M [𝐻 + ] = 0.0700 𝑀

𝑝𝑂𝐻 = 14.00 − 𝑝𝐻 = 14.00 − 1.155 = 12.845

(f) Calculate the [OH-] in 0.0350 M H2SO4. [𝑂𝐻 − ] = 10−𝑝𝑂𝐻 = 10−12.845 = 1.43 × 10−13 𝑀

2. (a) Write the chemical formula of lithium hydroxide. LiOH

(½ pt)

(b) Write the balanced dissociation equation for lithium hydroxide in an aqueous solution.

(½ pt)

𝐿𝑖𝑂𝐻(𝑎𝑞) → 𝐿𝑖 + (𝑎𝑞) + 𝑂𝐻 − (𝑎𝑞) (g) Determine the [H+] in lithium hydroxide pH 11.50 [𝐻 + ] = 10−𝑝𝐻 = 10−11.50 = 3.2 × 10−12 𝑀

Answer (½ pt)

Work (1/4)

SF (1/4 pt)

(h) Calculate the pOH of lithium hydroxide pH 11.50 𝑝𝐻 + 𝑝𝑂𝐻 = 14.00

Answer (½ pt)

Work (1/4)

SF (1/4 pt)

𝑝𝑂𝐻 = 14.00 − 𝑝𝐻 = 14.00 − 11.50 = 2.50

Name __________________________________________________ Period ________ Date ______________________ (i) Calculate the [OH-] in lithium hydroxide pH 11.50 [𝑂𝐻 − ] = 10−𝑝𝑂𝐻 = 10−2.50 = 3.2 × 10−3 𝑀

Answer (½ pt)

Work (1/4)

SF (1/4 pt)

3. When pH paper is added to H2SO4 what color does it turn? red

(½ pt)

4. When pH paper is added to a lithium hydroxide solution, what color does it turn? blue

(½ pt)