Integration Revision 4
Integra(on Core 2 revision Joel Dean
What it is • Integra(on is the opposite of differen(a(on that we learnt in Core 1 • This means that we do the exact opposite of what we would do to differen(ate • Therefore you : 1. Add one to the power of the func(on 2. Then divide by the new power.
Nota(on of integra(on
Recognising integra(on • You recognise that you have to integrate through the use of the nota(on shown on the previous slide and then use the rule shown earlier to integrate the func(on • There may or may not be limits of the integra(on of the func(on but you must know what to do when there are limits. • YOU MUST USE THE CORRECT NOTATION!!
Example of integra(on • Try this example
Solu(on
In this ques(on you are not given limits but if you were to be given limits, aRer integra(ng the func(on you would subs(tute the higher limit into the func(on to get an answer and then you would subs(tute the lower limit to get an answer. ARer this you would minus the lower limit answer off the higher limit answer to solve the integra(on.
What it is • Integra(on is the opposite of differen(a(on that we learnt in Core 1 • This means that we do the exact opposite of what we would do to differen(ate • Therefore you : 1. Add one to the power of the func(on 2. Then divide by the new power.
Nota(on of integra(on
Recognising integra(on • You recognise that you have to integrate through the use of the nota(on shown on the previous slide and then use the rule shown earlier to integrate the func(on • There may or may not be limits of the integra(on of the func(on but you must know what to do when there are limits. • YOU MUST USE THE CORRECT NOTATION!!
Example of integra(on • Try this example
Solu(on
In this ques(on you are not given limits but if you were to be given limits, aRer integra(ng the func(on you would subs(tute the higher limit into the func(on to get an answer and then you would subs(tute the lower limit to get an answer. ARer this you would minus the lower limit answer off the higher limit answer to solve the integra(on.
