Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
8β’4
Lesson 23: The Defining Equation of a Line Student Outcomes ο§
Students know that two equations in the form of ππ₯ + ππ¦ = π and πβ²π₯ + πβ²π¦ = πβ² graph as the same line when
ο§
πβ² π
=
πβ² π
=
πβ² π
and at least one of π or π is nonzero.
Students know that the graph of a linear equation ππ₯ + ππ¦ = π, where π, π, and π are constants and at least one of π or π is nonzero, is the line defined by the equation ππ₯ + ππ¦ = π.
Lesson Notes Following the Exploratory Challenge is a Discussion that presents a theorem about the defining equation of a line (page 367) and then a proof of the theorem. The proof of the theorem is optional. The Discussion can end with the theorem and in place of the proof, students can complete Exercises 4β8 beginning on page 369. Whether you choose to discuss the proof or have students complete Exercises 4β8, it is important that students understand that two equations that are written differently can be the same and their graph will be the same line. This reasoning becomes important when you consider systems of linear equations. In order to make sense of βinfinitely many solutionsβ to a system of linear equations, students must know that equations that might appear to be different can have the same graph and represent the same line. Further, students should be able to recognize when two equations define the same line without having to graph each equation, which is the goal of this lesson. Students need graph paper to complete the Exploratory Challenge.
Classwork Exploratory Challenge/Exercises 1β3 (20 minutes) Students need graph paper to complete the exercises in the Exploratory Challenge. Students complete Exercises 1β3 in pairs or small groups. Exploratory Challenge/Exercises 1β3 1.
Sketch the graph of the equation ππ + ππ = ππ using intercepts. Then answer parts (a)β(f) that follow. π(π) + ππ = ππ ππ = ππ π=π The π-intercept is (π, π). ππ + π(π) = ππ ππ = ππ π=π The π-intercept is (π, π).
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
364 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
a.
Sketch the graph of the equation π = βππ + π on the same coordinate plane.
b.
What do you notice about the graphs of ππ + ππ = ππ and π = βππ + π? Why do you think this is so?
8β’4
The graphs of the equations produce the same line. Both equations go through the same two points, so they are the same line.
c.
Rewrite π = βππ + π in standard form. π = βππ + π ππ + π = π
d.
Identify the constants π, π, and π of the equation in standard form from part (c). π = π, π = π, and π = π
e.
Identify the constants of the equation ππ + ππ = ππ. Note them as πβ² , πβ², and πβ². πβ² = π, πβ² = π, and πβ² = ππ
f.
What do you notice about
πβ² πβ²
,
π π
, and
πβ² π
?
πβ² π πβ² π πβ² ππ = = π, = = π, and = =π π π π π π π Each fraction is equal to the number π.
2.
π π
Sketch the graph of the equation π = π + π using the π-intercept and the slope. Then answer parts (a)β(f) that follow. a.
Sketch the graph of the equation ππ β ππ = βππ using intercepts on the same coordinate plane. π(π) β ππ = βππ βππ = βππ π=π The π-intercept is (π, π). ππ β π(π) = βππ ππ = βππ π = βπ The π-intercept is (βπ, π).
b.
π π
What do you notice about the graphs of π = π + π and ππ β ππ = βππ? Why do you think this is so? The graphs of the equations produce the same line. Both equations go through the same two points, so they are the same line.
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
365 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
c.
8β’4
π π
Rewrite π = π + π in standard form. π π+π π π (π = π + π) π π ππ = π + π π=
βπ + ππ = π βπ(βπ + ππ = π) π β ππ = βπ
d.
Identify the constants π, π, and π of the equation in standard form from part (c). π = π, π = βπ, and π = βπ
e.
Identify the constants of the equation ππ β ππ = βππ. Note them as πβ² , πβ², and πβ². πβ² = π, πβ² = βπ, and πβ² = βππ
f.
What do you notice about
πβ² πβ²
,
π π
β²
, and ππ ?
πβ² π πβ² βπ πβ² βππ = = π, = = π, and = =π π π π βπ π βπ Each fraction is equal to the number π.
3.
π π
The graphs of the equations π = π β π and ππ β ππ = ππ are the same line. a.
π π
Rewrite π = π β π in standard form. π πβπ π π (π = π β π) π π ππ = ππ β ππ π=
βππ + ππ = βππ βπ(βππ + ππ = βππ) ππ β ππ = ππ
b.
Identify the constants π, π, and π of the equation in standard form from part (a). π = π, π = βπ, and π = ππ
c.
Identify the constants of the equation ππ β ππ = ππ. Note them as πβ² , πβ², and πβ². πβ² = π, πβ² = βπ, and πβ² = ππ
d.
What do you notice about β²
β²
πβ² πβ²
,
π π
πβ²
, and ? π
β²
π π π βπ π ππ = = π, = = π, and = =π π π π βπ π ππ Each fraction is equal to the number π.
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
366 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
e.
8β’4
You should have noticed that each fraction was equal to the same constant. Multiply that constant by the standard form of the equation from part (a). What do you notice? ππ β ππ = ππ π(ππ β ππ = ππ) ππ β ππ = ππ After multiplying the equation from part (a) by π, I noticed that it is the exact same equation that was given.
Discussion (15 minutes) Following the statement of the theorem is an optional proof of the theorem. Below the proof are Exercises 4-8 (beginning on page 369) that can be completed instead of the proof. ο§
What did you notice about the equations you graphed in each of Exercises 1β3? οΊ
ο§
In each case, the graphs of the equations are the same line.
What you observed in Exercises 1β3 can be summarized in the following theorem: THEOREM: Suppose π, π, π, πβ² , π β² , and πβ² are constants, where at least one of π or π is nonzero, and one of πβ² or πβ² is nonzero .
MP.8
(1) If there is a nonzero number π so that πβ² = π π, π β² = π π, and π β² = π π, then the graphs of the equations ππ₯ + ππ¦ = π and πβ² π₯ + π β² π¦ = πβ² are the same line. (2) If the graphs of the equations ππ₯ + ππ¦ = π and πβ² π₯ + π β² π¦ = πβ² are the same line, then there exists a nonzero number π so that πβ² = π π, π β² = π π, and π β² = π π. The optional part of the discussion begins here. ο§
We want to show that (1) is true. We need to show that the graphs of the equations ππ₯ + ππ¦ = π and πβ² π₯ + π β² π¦ = πβ² are the same. What information are we given in (1) that will be useful in showing that the two equations are the same? οΊ
ο§
We are given that πβ² = π π, π β² = π π, and π β² = π π. We can use substitution in the equation πβ² π₯ + π β² π¦ = πβ² since we know what πβ² ,π β² , and πβ² are equal to.
Then by substitution, we have πβ² π₯ + π β² π¦ = π β² π ππ₯ + π ππ¦ = π π. By the distributive property π (ππ₯ + ππ¦) = π π. Divide both sides of the equation by π ππ₯ + ππ¦ = π. Which means the graph of πβ² π₯ + π β² π¦ = πβ² is equal to the graph of +ππ¦ = π . That is, they represent the same line. Therefore, we have proved (1).
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
367 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
ο§
8β’4
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
To prove (2), we will assume that π, π β 0, that is, we are not dealing with horizontal or vertical lines. Proving (2) will require us to rewrite the given equations ππ₯ + ππ¦ = π and πβ² π₯ + π β² π¦ = πβ² in slope-intercept form. Rewrite the equations. οΊ
ππ₯ + ππ¦ = π ππ¦ = βππ₯ + π π π π π¦=β π₯+ π π π π π π¦=β π₯+ π π
οΊ
πβ² π₯ + π β² π¦ = π β² π β² π¦ = βπβ² π₯ + π β² πβ² πβ² πβ² π¦ = β π₯ + πβ² πβ² πβ² β² π πβ² π¦ = β β²π₯+ β² π π π
π
πβ²
π
π
πβ²
ο§
We will refer to π¦ = β π₯ + as (A) and π¦ = β
ο§
What are the slopes of (A) and (B)? οΊ
ο§
The slope of (A) is β
π π
π₯+
πβ² πβ²
as (B).
, and the slope of (B) is β πβ² . πβ²
Since we know that the two lines are the same, we know the slopes must be the same. β
π πβ² =β β² π π
When we multiply both sides of the equation by β1, we have π πβ² = . π πβ² π
πβ²
Scaffolding:
π
π
Students may need to see the intermediate steps in the
By the multiplication property of equality, we can rewrite =
β² as
πβ² πβ² = . π π
π
πβ²
π
πβ²
rewriting of =
as
πβ² π
=
πβ² π
.
Notice that this proportion is equivalent to the original form. ο§
οΊ ο§
π
π
πβ²
π
π
πβ²
What are the π¦-intercepts of π¦ = β π₯ + (A) and π¦ = β The π¦-intercept of (A) is
π π
π₯+
πβ² πβ²
(B)?
πβ²
, and the π¦-intercept of (B) is πβ².
Because we know that the two lines are the same, the π¦-intercepts will be the same. π πβ² = π πβ² We can rewrite the proportion. πβ² π β² = π π
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
368 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
Using the transitive property and the fact that β²
πβ² π
=
πβ² π
and
πβ² π
8β’4
πβ²
= , we can make the following statement: π
β²
π π πβ² = = . π π π Therefore, all three ratios are equal to the same number. Let this number be π . πβ² πβ² πβ² = π , = π , = π π π π We can rewrite this to state that πβ² = π π, π β² = π π, and π β² = ππ . Therefore, (2) is proved. ο§
When two equations are the same, i.e., their graphs are the same line, we say that any one of those equations is the defining equation of the line.
Exercises 4β8 (15 minutes) Students complete Exercises 4β8 independently or in pairs. Consider having students share the equations they write for each exercise while others in the class verify which equations have the same line as their graphs. Exercises 4β8 4.
Write three equations whose graphs are the same line as the equation ππ + ππ = π. Answers will vary. Verify that students have multiplied π, π, and π by the same constant when they write the new equation.
5.
π π
Write three equations whose graphs are the same line as the equation π β ππ = . Answers will vary. Verify that students have multiplied π, π, and π by the same constant when they write the new equation.
6.
Write three equations whose graphs are the same line as the equation βππ + ππ = βπ. Answers will vary. Verify that students have multiplied π, π, and π by the same constant when they write the new equation.
7.
Write at least two equations in the form ππ + ππ = π whose graphs are the line shown below.
Answers will vary. Verify that students have the equation βπ + ππ = βπ in some form.
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
369 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
8.
8β’4
Write at least two equations in the form ππ + ππ = π whose graphs are the line shown below.
Answers will vary. Verify that students have the equation ππ + ππ = π in some form.
Closing (5 minutes) Summarize, or ask students to summarize, the main points from the lesson: ο§
We know that when the graphs of two equations are the same line it is because they are the same equation in different forms.
ο§
We know that even if the equations with the same line as their graph look different (i.e., different constants or different forms) that any one of those equations can be referred to as the defining equation of the line.
Lesson Summary Two equations define the same line if the graphs of those two equations are the same given line . Two equations that define the same line are the same equation, just in different forms. The equations may look different (different constants, different coefficients, or different forms). When two equations are written in standard form, ππ + ππ = π and πβ² π + πβ² π = πβ², they define the same line when
πβ² π
=
πβ² π
=
πβ² π
is true.
Exit Ticket (5 minutes)
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
370 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
Name
8β’4
Date
Lesson 23: The Defining Equation of a Line Exit Ticket 1.
Do the graphs of the equations β16π₯ + 12π¦ = 33 and β4π₯ + 3π¦ = 8 graph as the same line? Why or why not?
2.
Given the equation 3π₯ β π¦ = 11, write another equation that will have the same graph. Explain why.
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
371 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
8β’4
Exit Ticket Sample Solutions 1.
Do the graphs of the equations βπππ + πππ = ππ and βππ + ππ = π graph as the same line? Why or why not? No, in the first equation π = βππ, π = ππ, and π = ππ, and in the second equation πβ = βπ, πβ = π, and πβ = π. Then, πβ² π
=
π πβ²
βπ βππ
= ,
π π
=
π ππ
π
πβ²
π
π
= , but
=
π ππ
=
π
.
ππ
Since each fraction does not equal the same number, then they do not have the same graph.
2.
Given the equation ππ β π = ππ, write another equation that will have the same graph. Explain why. Answers will vary. Verify that the student has written an equation that defines the same line by showing that the fractions
πβ² π
=
πβ² π
=
πβ² π
= π, where π is some constant.
Problem Set Sample Solutions Students practice identifying pairs of equations as the defining equation of a line or two distinct lines. 1.
Do the equations π + π = βπ and ππ + ππ = βπ define the same line? Explain. Yes, these equations define the same line. When you compare the constants from each equation you get πβ² π πβ² π πβ² βπ = = π, = = π, and = = π. π π π π π βπ When I multiply the first equation by π, I get the second equation. (π + π = βπ)π ππ + ππ = βπ Therefore, these equations define the same line.
2.
π π
Do the equations π = β π + π and πππ + ππ = ππ define the same line? Explain. Yes, these equations define the same line. When you rewrite the first equation in standard form you get π π=β π+π π π (π = β π + π) π π ππ = βππ + π ππ + ππ = π. When you compare the constants from each equation you get πβ² ππ πβ² π πβ² ππ = = π, = = π, and = = π. π π π π π π When I multiply the first equation by π, I get the second equation. (ππ + ππ = π)π πππ + ππ = ππ Therefore, these equations define the same line.
Lesson 23: Date:
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
372 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 23
NYS COMMON CORE MATHEMATICS CURRICULUM
3.
8β’4
Write an equation that would define the same line as ππ β ππ = π. Answers will vary. Verify that the student has written an equation that defines the same line by showing that the fractions
4.
πβ² π
=
πβ² π
=
πβ² π
= π, where π is some constant.
Challenge: Show that if the two lines given by ππ + ππ = π and πβ² π + πβ² π = πβ² are the same when π = π (vertical lines), then there exists a non-zero number π, so that πβ² = ππ, πβ² = ππ, and πβ² = ππ. When π = π, then the equations are ππ = π and πβ² π = πβ². We can rewrite the equations as π =
π πβ² and π = . π πβ²
Because the equations graph as the same line, then we know that π πβ² = π πβ² and we can rewrite those fractions as π β² πβ² = . π π These fractions are equal to the same number. Let that number be π. Then πβ² = ππ and πβ² = ππ.
5.
πβ² π
= π and
πβ² π
= π. Therefore,
Challenge: Show that if the two lines given by ππ + ππ = π and πβ² π + πβ² π = πβ² are the same when π = π (horizontal lines), then there exists a non-zero number π, so that πβ² = ππ, πβ² = ππ, and πβ² = ππ. When π = π, then the equations are ππ = π and πβ²π = πβ². We can rewrite the equations as π =
π πβ² and π = . π πβ²
Because the equations graph as the same line, then we know that their slopes are the same. π πβ² = π πβ² We can rewrite the proportion. π β² πβ² = π π These fractions are equal to the same number. Let that number be π. Then β²
and π = ππ.
Lesson 23: Date:
πβ² π
= π and
πβ² π
= π. Therefore, πβ² = ππ
The Defining Equation of a Line 11/19/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
373 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.