NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 4
8β’3
Lesson 4: Fundamental Theorem of Similarity (FTS) Student Outcomes ο§
Students experimentally verify the properties related to the Fundamental Theorem of Similarity (FTS).
Lesson Notes The goal of this activity is to show students the properties of the Fundamental Theorem of Similarity (FTS), in terms of dilation. FTS states that given a dilation from center π and points π and π (points π, π, π are not collinear), the segments formed when you connect π to π and πβ² to πβ², are parallel. More surprising is that |πβ²πβ²| = π|ππ|. That is, the segment ππ, even though it was not dilated as points π and π were, dilates to segment πβ²πβ² and the length of segment πβ²πβ² is the length of segment ππ multiplied by the scale factor. The following picture refers to the activity suggested in the classwork discussion below. Also, consider showing the diagram (without the lengths of segments), and ask students to make conjectures about the relationships between the lengths of segments ππ and πβ²πβ².
Classwork Discussion (30 minutes) For this discussion, students will need a piece of lined paper, a centimeter ruler, a protractor, and a four-function (or scientific) calculator. ο§
The last few days we have focused on dilation. We now want to use what we know about dilation to come to some conclusions about the concept of similarity in general.
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
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Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
ο§
8β’3
A regular piece of notebook paper can be a great tool for discussing similarity. What do you notice about the lines on the notebook paper? οΊ
The lines on the notebook paper are parallel, that is, they never intersect.
ο§
Keep that information in mind as we proceed through this activity. On the first line of your paper, mark a point π. We will use this as our center.
ο§
Mark the point π a few lines down from the center π. From point π, draw a ray βββββ ππ . Now, choose a πβ² farther down the ray, also on one of the lines of the notebook paper. For example, you may have placed point π three lines down from the center, and point πβ² five lines down from the center.
ο§
Use the definition of dilation to describe the lengths along this ray. οΊ
ο§
By definition of dilation, |ππβ²| = π|ππ|.
Recall that we can calculate the scale factor using the following computation:
|ππβ² | |ππ|
= π. In my example, the
5 3
scale factor π = because ππβ² is 5 lines from the center, and ππ is 3 lines down. On the top of your paper, write down the scale factor that you have obtained. ο§
Now draw another ray, ββββββ ππ . Use the same scale factor to mark points π and πβ². In my example, I would place π three lines down, and πβ² five lines down from the center.
ο§
Now connect point π to point π and point πβ² to point πβ². What do you notice about lines ππ and πβ²πβ²? οΊ
ο§
Use your protractor to measure angles β πππ and β ππβ²πβ². What do you notice and why is it so? οΊ
ο§
Angles β πππ and β ππβ²πβ² are equal in measure. They must be equal in measure because they are corresponding angles of parallel lines (ππ and πβ²πβ²) cut by a transversal (ray βββββ ππ ).
(Consider asking students to write their answers to the following question in their notebooks and to justify their answers.) Now, without using your protractor, what can you say about angles β πππ and β ππβ²πβ²? οΊ
ο§
The lines ππ and πβ²πβ² fall on the notebook lines, which means that lines ππ and πβ²πβ² are parallel lines.
These angles are also equal for the same reason; they are corresponding angles of parallel lines (lines ππ and πβ²πβ²) cut by a transversal (ray ββββββ ππ ).
Use your centimeter ruler to measure the lengths of segments ππ and ππβ². By definition of dilation, we expect |ππβ²| = π|ππ| (that is, we expect the length of segment ππβ² to be equal to the scale factor times the length of segment ππ). Verify that this is true. Do the same for lengths of segments ππ and ππβ². οΊ
Sample of what student work may look like:
Lesson 4: Date:
Note to Teacher: Using a centimeter ruler will make it easier for students to come up with a precise measurement. Also, let students know that it is okay if their measurements are off by a tenth of a centimeter, because that difference can be attributed to human error.
Fundamental Theorem of Similarity (FTS) 10/30/14
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45 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
ο§
8β’3
Bear in mind that we have dilated points π and π from center π along their respective rays. Do you expect the segments ππ and πβ²πβ² to have the relationship |πβ²πβ²| = π|ππ|? οΊ
(Some students may say yes. If they do, ask for a convincing argument. At this point they have knowledge of dilating segments but that is not what we have done here. We have dilated points and then connected them to draw the segments.)
ο§
Measure the segments ππ and πβ²πβ² to see if they have the relationship |πβ²πβ²| = π|ππ|.
ο§
It should be somewhat surprising that, in fact, segments ππ and πβ²πβ² enjoy the same properties as the segments that we actually dilated.
ο§
Now mark a point π΄ on line ππ between points π and π. Draw a ray from center π through point π΄ and then mark π΄β² on the line πβ²πβ². Do you think |πβ²π΄β²| = π|ππ΄|? Measure the segments and use your calculator to check. οΊ
ο§
Now, mark a point π΅ on the line ππ but this time not on the segment ππ (i.e., not between points π and π). Again, draw the ray from center π through point π΅, and mark the point π΅β² on the line πβ²πβ². Select any segment, π΄π΅, ππ΅, ππ΅, and verify that it has the same property as the others. οΊ
ο§
Sample of what student work may look like:
Will this always happen, no matter the scale factor or placement of points π, π, π΄, and π΅? οΊ
ο§
Students should notice that these new segments also have the same properties as the dilated segments.
Yes, I believe this is true. One main reason is that everyone in class probably picked different points and Iβm sure many of us used different scale factors.
Describe the rule or pattern that we have discovered in your own words.
MP.8 Encourage students to write and collaborate with a partner to answer this question. Once students have finished their work, lead a discussion that crystallizes the information in the theorem that follows. ο§
We have just experimentally verified the properties of the Fundamental Theorem of Similarity (FTS) in terms of dilation. Namely, that the parallel line segments connecting dilated points are related by the same scale factor as the segments that are dilated. Theorem: Given a dilation with center π and scale factor π, then for any two points π and π in the plane so that π, π, and π are not collinear, the lines ππ and πβ²πβ² are parallel, where πβ² = π·ππππ‘πππ(π) and πβ² = π·ππππ‘πππ(π), and furthermore, |πβ²πβ²| = π|ππ|.
Ask students to paraphrase the theorem in their own words or offer them the following version of the theorem: FTS states that given a dilation from center π and points π and π (points π, π, and π are not on the same line), the segments formed when you connect π to π and πβ² to πβ² are parallel. More surprising is the fact that the segment ππ, even though it was not dilated as points π and π were, dilates to segment πβ² πβ² , and the length of segment πβ²πβ² is the length of segment ππ multiplied by the scale factor. ο§
Now that we are more familiar with properties of dilations and FTS, we will begin using these properties in the next few lessons to do things like verify similarity of figures.
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
46 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
8β’3
Exercise (5 minutes) Exercise In the diagram below, points πΉ and πΊ have been dilated from center πΆ by a scale factor of π = π.
a.
If the length of |πΆπΉ| = π. π cm, what is the length of |πΆπΉβ² |? |πΆπΉβ² | = π(π. π) = π. π cm
b.
If the length of |πΆπΊ| = π. π cm, what is the length of |πΆπΊβ² |? |πΆπΊβ² | = π(π. π) = ππ. π cm
c.
Connect the point πΉ to the point πΊ and the point πΉβ² to the point πΊβ². What do you know about lines πΉπΊ and πΉ β² πΊβ² ? The lines πΉπΊ and πΉβ²πΊβ² are parallel.
d.
What is the relationship between the length of segment πΉπΊ and the length of segment πΉβ² πΊβ²? The length of segment πΉβ²πΊβ² will be equal to the length of segment πΉπΊ, times the scale factor of π (i.e., |πΉβ² πΊβ² | = π|πΉπΊ|).
e.
Identify pairs of angles that are equal in measure. How do you know they are equal? β πΆπΉπΊ = β πΆπΉβ²πΊβ² and β πΆπΊπΉ = β πΆπΊβ² πΉβ². They are equal because they are corresponding angles of parallel lines cut by a transversal.
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
47 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
8β’3
Closing (5 minutes) Summarize, or ask students to summarize, the main points from the lesson. ο§
We know that the following is true: If |ππβ²| = π|ππ| and |ππβ²| = π|ππ|, then |πβ²πβ²| = π|ππ|. In other words, under a dilation from a center with scale factor π, a segment multiplied by the scale factor results in the length of the dilated segment.
ο§
We also know that the lines ππ and πβ²πβ² are parallel.
ο§
We verified the Fundamental Theorem of Similarity in terms of dilation using an experiment with notebook paper.
Lesson Summary Theorem: Given a dilation with center πΆ and scale factor π, then for any two points π· and πΈ in the plane so that πΆ, π·, and πΈ are not collinear, the lines π·πΈ and π·β²πΈβ² are parallel, where π·β² = π«πππππππ(π·) and πΈβ² = π«πππππππ(πΈ), and furthermore, |π·β²πΈβ²| = π|π·πΈ|.
Exit Ticket (5 minutes)
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
48 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
Name ___________________________________________________
8β’3
Date____________________
Lesson 4: Fundamental Theorem of Similarity (FTS) Exit Ticket Steven sketched the following diagram on graph paper. He dilated points π΅ and πΆ from point π. Answer the following questions based on his drawing. 1.
What is the scale factor π? Show your work.
2.
Verify the scale factor with a different set of segments.
3.
Which segments are parallel? How do you know?
4.
Are β ππ΅πΆ and β ππ΅β²πΆβ² right angles? How do you know?
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
49 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
8β’3
Exit Ticket Sample Solutions Steven sketched the following diagram on graph paper. He dilated points π© and πͺ from point πΆ. Answer the following questions based on his drawing. 1.
What is the scale factor π? Show your work. |πΆπ©β² | = π|πΆπ©| π =πΓπ π =π π
2.
Verify the scale factor with a different set of segments. |π©β² πͺβ² | = π|π©πͺ| π=πΓπ π =π π
3.
Which segments are parallel? How do you know? Segments π©πͺ and π©β²πͺβ² are parallel since they lie on the grid lines of the paper, which are parallel.
4.
Are β πΆπ©πͺ and β πΆπ©β²πͺβ² right angles? How do you know? The grid lines on graph paper are perpendicular, and since perpendicular lines form right angles, β πΆπ©πͺ and β πΆπ©β²πͺβ² are right angles.
Problem Set Sample Solutions Students verify that the Fundamental Theorem of Similarity holds true when the scale factor π is 0 < π < 1. 1.
Use a piece of notebook paper to verify the Fundamental Theorem of Similarity for a scale factor π that is π < π < π. οΌ
Mark a point πΆ on the first line of notebook paper.
οΌ
ββββββ . Mark the point π·β² on the Mark the point π· on a line several lines down from the center πΆ. Draw a ray, πΆπ· ray, and on a line of the notebook paper, closer to πΆ than you placed point π·. This ensures that you have a scale factor that is π < π < π. Write your scale factor at the top of the notebook paper.
οΌ
Draw another ray, ββββββ πΆπΈ, and mark the points πΈ and πΈβ² according to your scale factor.
οΌ
Connect points π· and πΈ. Then, connect points π·β² and πΈβ².
οΌ
Place a point π¨ on line π·πΈ between points π· and πΈ. Draw ray ββββββ πΆπ¨. Mark the point π¨β² at the intersection of line π·β²πΈβ² and ray ββββββ πΆπ¨.
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
50 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
8β’3
Sample student work shown in the picture below:
a.
Are lines π·πΈ and π·β²πΈβ² parallel lines? How do you know? Yes, the lines π·πΈ and π·β²πΈβ² are parallel. The notebook lines are parallel, and these lines fall on the notebook lines.
b.
Which, if any, of the following pairs of angles are equal in measure? Explain. i.
β πΆπ·πΈ and β πΆπ·β²πΈβ²
ii.
β πΆπ¨πΈ and β πΆπ¨β²πΈβ²
iii.
β πΆπ¨π· and β πΆπ¨β²π·β²
iv.
β πΆπΈπ· and β πΆπΈβ²π·β²
All four pairs of angles are equal in measure because each pair of angles are corresponding angles of parallel lines cut by a transversal. In each case, the parallel lines are line π·πΈ and line π·β² πΈβ² , and the transversal is the respective ray.
c.
Which, if any, of the following statements are true? Show your work to verify or dispute each statement. i.
|πΆπ·β²| = π|πΆπ·|
ii.
|πΆπΈβ²| = π|πΆπΈ|
iii.
|π·β²π¨β²| = π|π·π¨|
iv.
|π¨β²πΈβ²| = π|π¨πΈ|
All four of the statements are true. Verify that students have shown that the length of the dilated segment was equal to the scale factor multiplied by the original segment length.
d.
Do you believe that the Fundamental Theorem of Similarity (FTS) is true even when the scale factor is π < π < π. Explain. Yes, because I just experimentally verified the properties of FTS for when the scale factor is π < π < π.
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
51 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
2.
8β’3
Caleb sketched the following diagram on graph paper. He dilated points π© and πͺ from center πΆ.
a.
What is the scale factor π? Show your work. |πΆπ©β² | = π|πΆπ©| π =πΓπ π =π π π =π π
b.
Verify the scale factor with a different set of segments. |π©β² πͺβ² | = π|π©πͺ| π =πΓπ π =π π π =π π
c.
Which segments are parallel? How do you know? Segment π©πͺ and π©β²πͺβ² are parallel. They lie on the lines of the graph paper, which are parallel.
d.
Which angles are equal in measure? How do you know? β πΆπ©β² πͺβ² = β πΆπ©πͺ, and β πΆπͺβ² π©β² = β πΆπͺπ© because they are corresponding angles of parallel lines cut by a transversal.
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
52 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 4
NYS COMMON CORE MATHEMATICS CURRICULUM
3.
8β’3
Points π© and πͺ were dilated from center πΆ.
a.
What is the scale factor π? Show your work. |πΆπͺβ² | = π|πΆπͺ| π= πΓπ π =π π π=π
b.
If the length of |πΆπ©| = π, what is the length of |πΆπ©β² |? |πΆπ©β² | = π|πΆπ©| |πΆπ©β² | = π Γ π |πΆπ©β² | = ππ
c.
How does the perimeter of triangle πΆπ©πͺ compare to the perimeter of triangle πΆπ©β²πͺβ²? The perimeter of triangle πΆπ©πͺ is ππ units, and the perimeter of triangle πΆπ©β²πͺβ² is ππ units.
d.
Did the perimeter of triangle πΆπ©β²πͺβ² = π Γ (perimeter of triangle πΆπ©πͺ)? Explain. Yes, the perimeter of triangle πΆπ©β²πͺβ² was twice the perimeter of triangle πΆπ©πͺ, which makes sense because the dilation increased the length of each segment by a scale factor of π. That means that each side of triangle πΆπ©β²πͺβ² was twice as long as each side of triangle πΆπ©πͺ.
Lesson 4: Date:
Fundamental Theorem of Similarity (FTS) 10/30/14
Β© 2014 Common Core, Inc. Some rights reserved. commoncore.org
53 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.