Median: 6.5; Mode

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Lesson Warm Up 25

25

d. The outlier is 47. The range with the outlier is 43. The range without the outlier is 3. The mode with and without the outlier is 5. The median with the outlier is 5.5. The median without the outlier is 5. The mean with the outlier is 10.6. The mean without the outlier is 5.4. The standard deviation with the outlier is 13.8. The standard deviation without the outlier is 0.9.

1. discrete 2. -12.25 3. 0.0625 Lesson Practice 25 a. Mean: 6; Median: 6.5; Mode: 7 b. Range: 10; Standard deviation: 3.5 c. Range: 17; Standard deviation: 5.1

e. 1

2

3

4

5

6

f. The mean is about 111.4. The standard deviation is about 25.1.

© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.

LSN 25–1

Saxon Algebra 2

Lesson

25

17. (6, -4)

Practice 25

6. 6x4 - 9x3

18. The graph of P1 + P2 is a vertical translation (shift) of the graph of P1. Possible explanation: If P2 does not equal 0, but has degree 0, then it is a nonzero constant function. So, P1 + P2 is the function obtained by adding the nonzero constant P2 to P1.

7. (x + 5)(2x - 1)

19. a. 74,820 singles

1. 25 2. -9 3. -3x9y24 4. x > 6 -8 -6 -4 -2

⎡ 2 5. ⎢ ⎣-3

0

2

4

6

8

10⎤  2⎦

8. x = -4, y = 5

b. 52,888 singles

9. x = 5, y = -1

c. 21,932 more singles per hour

10. mean: 8; median: 10

20. a. 3

11. mean: 2.25; median: 2.5 12. mean: 8.8; median: 13 13. l = x - 12 in., w = x - 12 in. 14. B

b. Adding a border of 3, is the same as adding 24 inches to each side. Therefore (36 + 24)(56 + 24) = 4800 sq. inches.

15. (4, -1) 16. (-3, 3) © 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.

LSN 25–2

Saxon Algebra 2

Lesson 21. a.

23. a. 29.95 + 0.40m + 25 = 114.95

Lunch Person Drink Sandwich Snack Alea

1

2

2

Cory

2

2

1

Troy

2

1

3

b. m = 150 minutes c. 29.95 + 0.40(150) + 25 = 29.95 + 60 + 25 = 114.95

Cost Drink

$1.50

Sandwich

$4.00

Snack

$1.00

d. 400 minutes

⎡1 2 b. Lunch = 2 2 ⎣2 1



2⎤ 1 3⎦



24. Possible answer: ⎧5x + 2y = 7 ⎨ ⎩3x - 9y = -6, multiply the first equation by 3 and the second by -5 so that the coefficients of the x-terms are 15 and -15. 15 is the LCM of 5 and 3.

⎡1.50⎤ Cost = 4.00 ⎣1.00⎦





c. Cory

25. (2x - 5) 2 2 = 4x - 20x + 25

22. a. 2x2 - 32 = 0 b. x = 4 or x = -4 -4 2 c. 0 -3 8 8

⎪ ⎪

4 2 0 -3 8 -8

25

2 -1 = 0; 0



-2 1 =0 0



© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.

26. a. ⎪x - 147⎥ = 24 b. x = 123 or 171 27. The line does not fall. The slope is correct, but the line rises because the slope is positive.

LSN 25–3

Saxon Algebra 2

Lesson

25

28. a. Continuous function; Domain: all real numbers; Range: y≥0 b. Discontinuous function; Domain: all real numbers; Range: -1, 2 29. Mean: 8.7; Standard deviation: 1.71. 30. Yes; the constant of variation is 2.

© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.

LSN 25–4

Saxon Algebra 2