Page 1 III Year â Civil Engineering Email: info@engineeringolympiad ...
III Year – Civil Engineering Answer Keys: 1
D
2
B
3
B
4
C
5
A
6
D
7
A
8
B
9
B
10
A
11
A
12
A
13
C
14
C
15
D
16
D
17
D
18
C
19
C
20
D
21
B
22
B
23
A
24
A
25
D
26
B
27
A
28
A
29
C
30
A
31
B
32
A
33
D
34
B
35
C
36
A
37
D
38
B
39
B
40
B
41
B
42
D
43
B
44
C
45
A
46
B
47
C
48
A
49
D
50
D
Explanations: Section-I: General Ability
2.
a 2 b 2 ab 1 1 1 3 3 a b a b 1256 2454 3710
4.
152 2 / 1 154 160 80 2 90 80 10 / 3 30 3 44 30 14 / 4 11 4 29 11 18 / 5 5.8 5
154 6 / 2
5.
Practice is needed to avoid mistakes and rain to avoid drought.
6.
Local value of 9 Face value of 9 90000 9 89991
7.
Grumpy is a negative emotion.
8.
s TTT, TTH, THT, HTT, THH, HTH, HHT, HHH E event of getting at most two heads E= TTT, TTH, THT, HTT, THH, HTH, HHT PE
n E n s
7 8
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III Year – Civil Engineering 9.
To ‘mark something off’ is to make ‘something different from the others which is the most appropriate phrase to be used here. To ‘mark something out’ is to draw the outline of something.
10.
Let the principal be P and rate of interest be R%.
P× R ×8 100 = 8PR = 2 : 3 ∴ Required ratio = P × R ×12 12PR 100
11.
‘So conservative that’ is the correct conjunction here.
12.
A can finish his work in 30 days B can finish his work in 50 days Therefore, A’s one day work =
1 30
1 50 53 8 A B 's one day work is 150 150 1 150 A and B together finish the work 8 8 150
And B’s one day work =
14.
Let the number be xy. 10x y 6 x y 10x y 6x 6y 0 4x 5y x 5& y4 Number 54 Sum 5 4 9
16.
150 :1:: x : 3 150 1 x 3
=
x 3
= 150
x = 450 minutes
So, it takes 450 minutes or 7 hours 30 minutes to paint the other 3 walls. Email: [email protected], Website: www.engineeringolympiad.in
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III Year – Civil Engineering 17.
The most reasonable conclusion is choice (D), which pretty much just summarizes the evidence here: Some drugs can have effects the opposite of those intended. We cannot conclude, as (A) would, that these three types of drugs are the three major types. Nor can we conclude (B), which overreacts to the evidence. For all we know, most drugs may have such a single effect, and only these three types do not. (C) wants us to conclude that since opioid drugs are used to blunt sensory awareness, they tend to have the effects of increasing appetite and inducing sleep (that is, the opposite effects of stimulants). Well, not necessarily. If you chose (C), you were using outside information. It could be that opioids are used to decrease appetite, just like stimulants.
18.
Let the number of coins of each kind be x. ⇒ 5x + 2x +1x = 11520 ⇒ 8x = 11520 ⇒ x = 1440
20.
Percentage of Intermediate colleges where enrollment is below 120 are given by 526 620 674 717 681 100 5409 3218 100 59.49% . 5409
Section-II: Technical 21.
5g T 5a (1) 3a (2) 2 Solving 1& 2 2T 3g
23a 2 14g a 6 m s2 23 V u at 0 6 8 48m / s 7g
22.
T
2T
3
55
Using Bernoulli’s equation, P1 V2 ZS losses g 2g 62 1.22 0.1 2 9.81 2 9.81 6.66 m
5
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III Year – Civil Engineering 23.
We also know that maximum shear stress on the plane, 2
2
2 6x 100 xy 2xy 25 55.9 MPa 2 2
24.
W.C.B 23959' Quadrantal Bearing 23959' 180
N
5959' S 5959' W. E
W 1
2390 59 S
25.
As per IS 456 Minimum tensile reinforcement is AS 0.85 bd fy AS
26.
0.85 250 300 153.61 mm 2 . 415
C6 H12O6 6O2 6CO2 6H2O
TOC
Carbon formed 6 12 0.4 1 mole of organic susbs tan ce glu cos e 180
27.
Pyrolysis occurs in presence of heat and absence of O2 .
28.
1 2 D1 5 1 1 D2
1
1
1 2 27 5 1 0.86 130 2 0.8977 efficiency 89.77% 29.
500 MPa A
10 103 20 mm 2 500
side 20 4.47 mm. Email: [email protected], Website: www.engineeringolympiad.in
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III Year – Civil Engineering 30.
Difference between A and B 1.625 0.963 2.621 2.193
2 Rise from A to B 0.545
0.545
Correct reading of B = observed reading of B + collimation error – combined correction. 1.625 0.545 0.963 C 0.0673 1.08 0.8957 C C 0.1843 Error 0.1843 31.
Lateral thrust on gantry girder 10% of capacity of crane weight of crab
=10×(100+25) =12.5kN
3 t x z t y2 0 x y z
32.
.V
33.
b O
P Pe M A Z Z
A 150 mm 300 mm, Z
bd 2 , 6
P 500 103 N e 50 mm, L 10000 mm
QL 500 103 500 103 4 O 150 300 150 3002 150 3002 6 6 500 103 150 300 Q
3 50 6 Q 10 6 10 1 300 4 150 300 2
2 500 10 3 4 300 6 10 103
20 kN
34.
W 2Fcos W 2Fcos 2 10 cos60 10N
36.
Difference between northings of P and Q = Latitude of PQ P and Q Latitude of PQ 1287.7 1081.5 206.2 Departure of PQ 427.1 927.2 500.1 Length of PQ
206.2
2
500.1 540.942 m 541m. 2
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III Year – Civil Engineering 37.
Area needed for sludge thicknening, A
Qtu H0
200 m 3 / s 30sec 3m
2000 m 2
39.
40.
41.
Q1 Q3 Q 2 , 0.042 5 0.012 Q 2 ,Q 2 0.01828 m 3 s 4 0.01828 Q V2 2 A2 0.062 4 6.466 m s 16T 32T and normal stress = 3 d d 3 Ratio = 1: 2 Shear stress =
1 1 2 , f x N 2 ; f' x 3 , x k 1 x k x x 12
x
1 xk2 2 x k3
N
xk 3 Nx k 2 2 The positive number nearest to 12 which is a perfect square is 9 and
x 1 1 1 , x 0 , x1 0 3 12x 0 2 0.277778 3 2 9 3 x2
42.
x1 3 12x12 0.288066, x 3 0.28867, x 4 0.28867 2
1 0.28867 12
Z = -1,1 are the points lies outside the circle c: z
1 2
By Cauchy's integral theorem dz
z 1 z 1 =0 c
43.
A.E. is m2 6m 13 0 m1 3 2i and m 2 3 2i y=e3x A cos 2x Bsin 2x
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III Year – Civil Engineering
44.
1 1 1 4 0 3 3 2 4 Another Method: 1 4 3
1
1
2
4
6 0 8
1 4
6 8 0
R2 R3 1 3 4
1 2
R 2 R 2 3R 1 , R 3 R 3 R 2 4
1 0 0
1 1 4
1 7 4
6 26 24
8 24 0 3
45.
x
1
0
x
f t dt x t f t dt
x 1 d d f t dt x tf t dt dx 0 x dx
f x 1 0 xf x f x
1 1 1 ; f 1 0.5 x 1 11 2
46.
Volume of cylinder = r2h = (0.08)20.5 = 0.01005 m3 Mass of cylinder (m) = density volume = 78.41 Kg Moment of inertia = 0.5mr2 = 0.5(78.41)(0.082 )= 0.2509 kg.m2
47.
Q Cd a 2gH
2 0.6 0.1 2 9.81 200 30 10 2 4 0.027 m
3
sec
Q 0.027 3.43 m sec 2 a 0.1 4 Pr opelling force QV 600 0.027 3.43 55.55 N
Velocity of jet from orifice
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III Year – Civil Engineering 48.
At a plane at 20o with principal plane 2 1 2 x 1 cos 2 2 2 80 40 80 40 cos 40 73.22 N / mm 2 tensile 2 2 2 1 80 N / mm2 t 1 sin 2 12.86 N / mm 2 2
2 40 N / mm2
σ1
Resul tan t stress x 2 t 2
49.
75.32
2
12.86 76.41 N / mm 2 2
σ2
Moment of inertia about x-axis 3
3 bh 3 b 1 a.b I xx 2 2 a 12 2 12 48
ab3 I ab 2 Section mod ulus, xx 48 b y 24 2 A Plastic sec tion mod ulus Z p y1 y 2 2 1 a.b b b 2 2 6 6 ab 2 4 6 6 12 m3 12 12 ab 2 12 Shape factor 2 2. ab 24
50.
Design flow, Q
b
2
2000m3 24h 4000 m3 / day 12h 1day
Since tanks are used alternatively. Volume of only 1 tank will be used. So, Tank volume L B H 24 6 3 432m3 So,det ention time, t
V 432 0.108 days 2.592 hours 2.6 hours Q 4000
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D
2
B
3
B
4
C
5
A
6
D
7
A
8
B
9
B
10
A
11
A
12
A
13
C
14
C
15
D
16
D
17
D
18
C
19
C
20
D
21
B
22
B
23
A
24
A
25
D
26
B
27
A
28
A
29
C
30
A
31
B
32
A
33
D
34
B
35
C
36
A
37
D
38
B
39
B
40
B
41
B
42
D
43
B
44
C
45
A
46
B
47
C
48
A
49
D
50
D
Explanations: Section-I: General Ability
2.
a 2 b 2 ab 1 1 1 3 3 a b a b 1256 2454 3710
4.
152 2 / 1 154 160 80 2 90 80 10 / 3 30 3 44 30 14 / 4 11 4 29 11 18 / 5 5.8 5
154 6 / 2
5.
Practice is needed to avoid mistakes and rain to avoid drought.
6.
Local value of 9 Face value of 9 90000 9 89991
7.
Grumpy is a negative emotion.
8.
s TTT, TTH, THT, HTT, THH, HTH, HHT, HHH E event of getting at most two heads E= TTT, TTH, THT, HTT, THH, HTH, HHT PE
n E n s
7 8
Email: [email protected], Website: www.engineeringolympiad.in
IEO-2017 Partners & Sponsors:
1 of 8
III Year – Civil Engineering 9.
To ‘mark something off’ is to make ‘something different from the others which is the most appropriate phrase to be used here. To ‘mark something out’ is to draw the outline of something.
10.
Let the principal be P and rate of interest be R%.
P× R ×8 100 = 8PR = 2 : 3 ∴ Required ratio = P × R ×12 12PR 100
11.
‘So conservative that’ is the correct conjunction here.
12.
A can finish his work in 30 days B can finish his work in 50 days Therefore, A’s one day work =
1 30
1 50 53 8 A B 's one day work is 150 150 1 150 A and B together finish the work 8 8 150
And B’s one day work =
14.
Let the number be xy. 10x y 6 x y 10x y 6x 6y 0 4x 5y x 5& y4 Number 54 Sum 5 4 9
16.
150 :1:: x : 3 150 1 x 3
=
x 3
= 150
x = 450 minutes
So, it takes 450 minutes or 7 hours 30 minutes to paint the other 3 walls. Email: [email protected], Website: www.engineeringolympiad.in
IEO-2017 Partners & Sponsors:
2 of 8
III Year – Civil Engineering 17.
The most reasonable conclusion is choice (D), which pretty much just summarizes the evidence here: Some drugs can have effects the opposite of those intended. We cannot conclude, as (A) would, that these three types of drugs are the three major types. Nor can we conclude (B), which overreacts to the evidence. For all we know, most drugs may have such a single effect, and only these three types do not. (C) wants us to conclude that since opioid drugs are used to blunt sensory awareness, they tend to have the effects of increasing appetite and inducing sleep (that is, the opposite effects of stimulants). Well, not necessarily. If you chose (C), you were using outside information. It could be that opioids are used to decrease appetite, just like stimulants.
18.
Let the number of coins of each kind be x. ⇒ 5x + 2x +1x = 11520 ⇒ 8x = 11520 ⇒ x = 1440
20.
Percentage of Intermediate colleges where enrollment is below 120 are given by 526 620 674 717 681 100 5409 3218 100 59.49% . 5409
Section-II: Technical 21.
5g T 5a (1) 3a (2) 2 Solving 1& 2 2T 3g
23a 2 14g a 6 m s2 23 V u at 0 6 8 48m / s 7g
22.
T
2T
3
55
Using Bernoulli’s equation, P1 V2 ZS losses g 2g 62 1.22 0.1 2 9.81 2 9.81 6.66 m
5
Email: [email protected], Website: www.engineeringolympiad.in
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3 of 8
III Year – Civil Engineering 23.
We also know that maximum shear stress on the plane, 2
2
2 6x 100 xy 2xy 25 55.9 MPa 2 2
24.
W.C.B 23959' Quadrantal Bearing 23959' 180
N
5959' S 5959' W. E
W 1
2390 59 S
25.
As per IS 456 Minimum tensile reinforcement is AS 0.85 bd fy AS
26.
0.85 250 300 153.61 mm 2 . 415
C6 H12O6 6O2 6CO2 6H2O
TOC
Carbon formed 6 12 0.4 1 mole of organic susbs tan ce glu cos e 180
27.
Pyrolysis occurs in presence of heat and absence of O2 .
28.
1 2 D1 5 1 1 D2
1
1
1 2 27 5 1 0.86 130 2 0.8977 efficiency 89.77% 29.
500 MPa A
10 103 20 mm 2 500
side 20 4.47 mm. Email: [email protected], Website: www.engineeringolympiad.in
IEO-2017 Partners & Sponsors:
4 of 8
III Year – Civil Engineering 30.
Difference between A and B 1.625 0.963 2.621 2.193
2 Rise from A to B 0.545
0.545
Correct reading of B = observed reading of B + collimation error – combined correction. 1.625 0.545 0.963 C 0.0673 1.08 0.8957 C C 0.1843 Error 0.1843 31.
Lateral thrust on gantry girder 10% of capacity of crane weight of crab
=10×(100+25) =12.5kN
3 t x z t y2 0 x y z
32.
.V
33.
b O
P Pe M A Z Z
A 150 mm 300 mm, Z
bd 2 , 6
P 500 103 N e 50 mm, L 10000 mm
QL 500 103 500 103 4 O 150 300 150 3002 150 3002 6 6 500 103 150 300 Q
3 50 6 Q 10 6 10 1 300 4 150 300 2
2 500 10 3 4 300 6 10 103
20 kN
34.
W 2Fcos W 2Fcos 2 10 cos60 10N
36.
Difference between northings of P and Q = Latitude of PQ P and Q Latitude of PQ 1287.7 1081.5 206.2 Departure of PQ 427.1 927.2 500.1 Length of PQ
206.2
2
500.1 540.942 m 541m. 2
Email: [email protected], Website: www.engineeringolympiad.in
IEO-2017 Partners & Sponsors:
5 of 8
III Year – Civil Engineering 37.
Area needed for sludge thicknening, A
Qtu H0
200 m 3 / s 30sec 3m
2000 m 2
39.
40.
41.
Q1 Q3 Q 2 , 0.042 5 0.012 Q 2 ,Q 2 0.01828 m 3 s 4 0.01828 Q V2 2 A2 0.062 4 6.466 m s 16T 32T and normal stress = 3 d d 3 Ratio = 1: 2 Shear stress =
1 1 2 , f x N 2 ; f' x 3 , x k 1 x k x x 12
x
1 xk2 2 x k3
N
xk 3 Nx k 2 2 The positive number nearest to 12 which is a perfect square is 9 and
x 1 1 1 , x 0 , x1 0 3 12x 0 2 0.277778 3 2 9 3 x2
42.
x1 3 12x12 0.288066, x 3 0.28867, x 4 0.28867 2
1 0.28867 12
Z = -1,1 are the points lies outside the circle c: z
1 2
By Cauchy's integral theorem dz
z 1 z 1 =0 c
43.
A.E. is m2 6m 13 0 m1 3 2i and m 2 3 2i y=e3x A cos 2x Bsin 2x
Email: [email protected], Website: www.engineeringolympiad.in
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6 of 8
III Year – Civil Engineering
44.
1 1 1 4 0 3 3 2 4 Another Method: 1 4 3
1
1
2
4
6 0 8
1 4
6 8 0
R2 R3 1 3 4
1 2
R 2 R 2 3R 1 , R 3 R 3 R 2 4
1 0 0
1 1 4
1 7 4
6 26 24
8 24 0 3
45.
x
1
0
x
f t dt x t f t dt
x 1 d d f t dt x tf t dt dx 0 x dx
f x 1 0 xf x f x
1 1 1 ; f 1 0.5 x 1 11 2
46.
Volume of cylinder = r2h = (0.08)20.5 = 0.01005 m3 Mass of cylinder (m) = density volume = 78.41 Kg Moment of inertia = 0.5mr2 = 0.5(78.41)(0.082 )= 0.2509 kg.m2
47.
Q Cd a 2gH
2 0.6 0.1 2 9.81 200 30 10 2 4 0.027 m
3
sec
Q 0.027 3.43 m sec 2 a 0.1 4 Pr opelling force QV 600 0.027 3.43 55.55 N
Velocity of jet from orifice
Email: [email protected], Website: www.engineeringolympiad.in
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7 of 8
III Year – Civil Engineering 48.
At a plane at 20o with principal plane 2 1 2 x 1 cos 2 2 2 80 40 80 40 cos 40 73.22 N / mm 2 tensile 2 2 2 1 80 N / mm2 t 1 sin 2 12.86 N / mm 2 2
2 40 N / mm2
σ1
Resul tan t stress x 2 t 2
49.
75.32
2
12.86 76.41 N / mm 2 2
σ2
Moment of inertia about x-axis 3
3 bh 3 b 1 a.b I xx 2 2 a 12 2 12 48
ab3 I ab 2 Section mod ulus, xx 48 b y 24 2 A Plastic sec tion mod ulus Z p y1 y 2 2 1 a.b b b 2 2 6 6 ab 2 4 6 6 12 m3 12 12 ab 2 12 Shape factor 2 2. ab 24
50.
Design flow, Q
b
2
2000m3 24h 4000 m3 / day 12h 1day
Since tanks are used alternatively. Volume of only 1 tank will be used. So, Tank volume L B H 24 6 3 432m3 So,det ention time, t
V 432 0.108 days 2.592 hours 2.6 hours Q 4000
Email: [email protected], Website: www.engineeringolympiad.in
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