Physics 1307 Quiz 6 Solution = T=2 mk =2 1000kg ...
Physics 1307 Quiz 6 Solution The shock absorbers in an old car with mass 1000 kg are completely worn out. When a 980N person climbs slowly into the car, its center of gravity sinks 2.8 cm. When the car, with the person aboard, hits a bump, the car starts oscillating up and down in SHM. Find the period of the oscillation. To obtain the period we need first to find the spring 's constant. The situation is described in the figure below: F=kx
mg
x
Thus: F 980 N k= = = 3.5×104 N / m x 0.028m Therefore the period is:
T =2
m k
=2
1000kg100kg 3.5×10 4 N /m 2
=1.11 s
where we have used the fact that the mass of the person is m =
980 N 9.8 m / s2
carperson system is 1100 kg. Useful equations:
F=kx
T =2
1/1
m k
s
=100kg and the total mass of the
mg
x
Thus: F 980 N k= = = 3.5×104 N / m x 0.028m Therefore the period is:
T =2
m k
=2
1000kg100kg 3.5×10 4 N /m 2
=1.11 s
where we have used the fact that the mass of the person is m =
980 N 9.8 m / s2
carperson system is 1100 kg. Useful equations:
F=kx
T =2
1/1
m k
s
=100kg and the total mass of the
