Problem Solving

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Name ________________________________________ Date __________________ Class__________________ LESSON

9-2

Problem Solving Characteristics of Quadratic Functions

Write the correct answer.

1. A superhero is trying to leap over a tall building. The function f(x) = −16x 2 + 200x gives the superhero’s height in feet as a function of time. The building is 612 feet high. Will the superhero make it over the building? Explain.

2. The graph shows the height of an arch support for a pedestrian bridge.

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3. The distance between the cables suspending a bridge and the water below is given by the function y = 0.02x 2 − 2x + 80. Find the vertex of the graph.

Find the zeros (if any) and axis of symmetry of this parabola. ____________________________________________

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After a heavy snowfall, Joe and Karin made an igloo. The dome of the igloo is in the shape of a parabola and the height of the igloo in inches is given by f(x) = −0.03x2 + 2.4x. Select the best answer.

4. Joe wants to place a support in the middle of the igloo, along the axis of symmetry. How far from the edge of the igloo should he place the support? A 24 in.

C 48 in.

B 40 in.

D 80 in.

7. What is the vertex of the parabola that Karin graphed?

H 48 in.

G 40 in.

J 80 in.

6. Karin graphs the parabola and looks at the zeros to see how wide the igloo is. What are the zeros of this parabola? A −80 and 80

C 0 and 80

B −40 and 40

D 40 and 80

H (48, 40)

G (40, 48)

J (80, 0)

8. Which graph below is the graph that Karin made?

5. Neither Joe nor Karin can stand up inside the igloo. How tall is the center of the igloo? (Hint: the top of the igloo is the vertex of the parabola.) F 24 in.

F (20, 36)

A

C

B

D

Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor.

9-17

Holt McDougal Algebra 1

4. x −2 −1 0 1 2

Practice C

y 8 2 0 2 8

1. −3 and 3

2. −6 and 0

3. no zeros

4. x = −3

5. x = 4

6. x = 1

7. x =

1 8

9. x = −

5.

3 8

11. (−2, 15)

8. x = −0.75 10. (1, −3) 3 17 12. (− , − ) 2 2

Review for Mastery

1. x = 3

2. x = 2

3. The axis of symmetry is x = −3. 4. The axis of symmetry is x = 0. 5. −10; 1; 10; 2; 5; x = 5 6. x = 1 7. x = 5; 5; 5; 0; y = 0; (5, 0)

6. (0, 0)

8. (1, 8)

7. upward; because a > 0.

9. The vertex is (−3, −27)

LESSON 9–2

Challenge

1. (−6, 0); (−3, −9); (0, 0)

Practice A

1. −4 and 0

2. −2

2. 0 = 36a − 6b + c; −9 = 9a − 3b + c; 0 = c

3. no zeros

4. x = 0

3. 1; 6; 0

5. x = −4

6. x = 5

⎧0 = 9a − 3b + c ⎪ 5. ⎨18 = c ; y = −2 x 2 + 18 ⎪0 = 9a + 3b + c ⎩

7. 1; 8; −4; x = −4; (−4, −4) 8. 1; −10; 5; x = 5; (5, 15) 9. 2; −8; 2; x = 2; (2, −11)

⎧0 = 25a − 5b + c ⎪ 6. ⎨0 = 4a + 2b + c ; y = x 2 + 3 x − 10 ⎪− 12.25 = 2.25a − 1.5b + c ⎩

Practice B

1. −6 and 1

2. no zeros

3. 5

4. x =

5. x = 3

6. x = −1

7. x = 1

8. x = 2

1 9. x = − 16 11. (−2, −22)

4. y = x 2 + 6x

7 2

Problem Solving

1. Yes; the vertex is (6.25, 625) and 625 > 612

10. (1, −5) 12. (−1, −36)

2. 0 and 50; x = 25

3. (50, 30)

4. B

5. H

6. C

7. G

8. D

Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor.

A22

Holt McDougal Algebra 1