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Bipartite Permutation Graphs are Reconstructible
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Bipartite Permutation Graphs are Reconstructible Toshiki Saitoh (ERATO) Joint work with Masashi Kiyomi (JAIST) and Ryuhei Uehara (JAIST) COCOA 2010 18-20/Dec/2010
Graph Reconstruction Conjecture
Deck of Graph G=(V, E): multi-set {G - v | v∈V} Preimage of multi-set D: a graph whose deck is D Deck of G
v1
v4
v1
v2
v3
v5
v3
v5
Preimage v2
v4
v2
v4
G-v2
v1 v3
v5
Graph G
v3
v5
G-v1
G-v4
v2
v4
v1
v2
v1
v5
v3
v4
G-v3
G-v5
Graph Reconstruction Conjecture
For any multi-set D of graphs with n-1 vertices, there is at most 1 preimage whose deck is D (n≧3).
Multi-set: D
Graph G
Different graph of G
Unlabeled graphs
Graph Reconstruction Conjecture
Proposed by Ulam and Kelly [1941]
Open problem
Reconstructible graph classes
Reconstructible: Its deck has only one preimage. regular graphs, trees, disconnected graphs, etc.
Our Result Bipartite Permutation Graphs are Reconstructible.
Bipartite Permutation Graphs
Permutation graph: graph that has a permutation diagram. 1
2
3
4
5
6
1
6 4
3 6 4 1 5 2 Permutation diagram
3 2 5 Permutation graph
Bipartite permutation graph: permutation graph that is bipartite. 1 2 3 4 5 6 7 8
3 5 6 1 2 8 4 7
Permutation diagram
1
2
4
7
3
5
6
8
Bipartite permutation graph
Bipartite Permutation Graphs Lemma 1
Induced subgraphs of a bipartite permutation graph are bipartite permutation graphs. 1 2 3 4 5 6 7 8
3 5 6 1 2 8 4 7
1
2
4
7
3
5
6
8
A preimage G is a bipartite permutation graph
Each graph in the deck of G is a bipartite permutation graph.
Bipartite Permutation Graphs Lemma 1
Induced subgraphs of a bipartite permutation graph are bipartite permutation graphs. Lemma 2 [Saitoh et al. 2009]
There exists at most four permutation diagrams for any connected bipartite permutation graph. horizontal-flip Rotation Vertical-flip
Vertical-flip
horizontal-flip Each permutation diagram of a graph in the deck can be obtained by removing one segment.
Theorem Bipartite permutation graphs are reconstructible.
Only show the connected case. Every
disconnected graphs are reconstructible.
Main Idea of Proof Uniquely
reconstruct a preimage.
By adding a segment uniquely to a permutation diagram of some graph in the deck. There are O(n2) candidates.
We show only one candidate is valid.
Choosing Valid Candidate
Using the degree of a polar vertex of the preimage.
Polar vertex: Left-most or right-most segment
Let
a vertex v be a polar vertex of the preimage G and deg(v) = p in G
There is a graph in the deck obtained by removing a vertex w adjacent to v. Clearly deg(v) = p-1 in the graph.
We know
the degree of the removing vertex w.
Degree sequence is reconstructible.[Greenwell and Hemminger 73]
v deg(w) = 2
deg(v): p-1 → p Using the deg(w) we have only one choice.
Finding the Degree of a Polar Vertex Lemma 3
G=(X, Y, E): Connected bipartite permutation graph. |X| and |Y| are reconstructible.
Using lemma 3 Choose connected
There are three possibilities of X-polar degree patterns.
p …
q-1
…
graphs with removing a vertex in Y.
…
p-1 …
…
p
q …
We can determine p and q.
…
q
…
…
Conclusion and Future Works
Our result
Bipartite permutation graphs are reconstructible.
Future works
Are the other graph classes reconstructible?
For example, interval graphs, permutation graphs, etc.
The number of preimages are at most n2.
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