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Chemical Equilibrium Extra Practice Questions
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Fall 2017
Chemical Equilibrium Extra Practice Questions 1. Write the equilibrium reaction equation for each of the following reactions a) 3H2(g) + N2(g) 2NH3(g) b) Mg(s) + 2HCl(aq) H2(g) + MgCl2(aq) c) 2HCl(aq) + Ca(OH)2(aq) CaCl2(s) + 2H2O(l) d) (HC3H3O2(aq) + NaHCo3(aq) NaC2H3O2(aq) + H2O(l) + CO2(g) ) x 4 2. Find the overall reaction rate for the following multi-step reactions. a) H2O(g) 2H2(g) + O2(g) k1 = 3.18 3O2(g) + 4Fe(s) 2Fe2O3(s) k2 = 0.12 b) CH4(g) + 2O2(g) CO2(g) + 2H2O(g) k1 = 1.11 CO2(g) + H2O(g) H2CO3(s) k2 = 0.99 c) HCl(aq) + NaOH(aq) NaCl(aq) + H2O(l) k1 = 357 NaCl(aq) + AgNO3(aq) NaNO3(aq) + AgCl(aq) k2 = 3.17 d) 2HCl(aq) Cl2(g) + H2(g) Mg(s) + HCl(aq) MgCl2(aq) + H2(g)
k-1 = 0.00123 k2 = 3.456
3. If the following reaction is carried out at 40 oC, what is the kc of the reaction? 4NH3(l) + 5O2(g) 4NO(g) + 6H2O(l) 10 atm 3 atm 4. If 7.5 moles of PCl3 is added to a reaction flask with a 6.3 moles of Cl2, what is the amount of PCl5 produced if the reaction has k = 1.32? 5. A mixture of natural gas (CH4(g)) and bromine (Br2(l)) was found to produce CBr4(s) and H2(g). This reaction is known to have a kc of 5.01. In order to test the equilibrium of the mixture, 1 M of CH4, 1 M of Br2, 2 M of CBr4, and 2 M of H2 are mixed in a 1000°C. a) Determine the Qc of the reaction and predict which direction the reaction will proceed. b) What is the equilibrium concentration of each component in the reaction, What is the equilibrium concentration of each equilibrium component in the reaction if the concentration of H2 is 2.15 M? 6. The following decomposition reaction was performed in a lab: H2CO3(aq) H2O(l) + CO2(aq) This reaction was found to have kc = 1.2 x 10-4 at 200 oC. Calculate the concentration of H2CO3, CO2, and H2O when 3.5 moles of H2CO3 were placed in the original flask. 1 © Copyright 2017 by Wizedemy Inc. All Rights Reserved. No part of this publication may be reproduced or transmitted in any form or by any means, or sorted in a data base or retrieval system, without the prior written permission Wizedemy Inc.
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