Grade 8 Unit 5 Assessment Defining, Evaluating, and Comparing Functions
Answer Key 1.
B
2.
8.EE.6 6.
A
π(π‘) = 250 β 2π‘
3.
8.EE.6 7.
8.EE.6 11 .
C
A
8.
13 .
A. N B. N C. Y D. N
4.
8.EE.6
8.EE.6 12 .
C
D
C
5.
8.EE.6 9.
C
8.EE.6
8.EE.6
π(π) = 3π β 2 14 .
A. F B. F C. T D. T
D 8.EE.6
10 .
D 8.EE.6
15 .
8 6 4 2
8.EE.6
8.EE.6
8.EE.6
8.EE.6
0 -5
-2
0
5
D: {π₯|π₯ = π } R: {π(π₯)|π(π₯) β₯ β1} 8.EE.6 16. Graphs may vary; check studentβs graph for accuracy in depicting a relation that is not a function. Possible explanation: The relation I created on the graph is not a function because it fails the vertical line test. As can be seen on my graph one of the inputs produces two outputs, which is not characteristic of a function. 8.EE.6