Lesson Warm Up 17 1. conjunction 2
Lesson
17
Warm Up 17 1. conjunction 2. -1 ≤ x ≤ 4 3. all real numbers Lesson Practice 17 a. x = 4 or x = -10 -12 -10 -8
-6
-4
-2
0
2
4
6
-2
0
2
4
6
8
5
6
7
8
b. x = 0 or x = 2 c. no solution 1 1 _ or d. x = _ 2 6
e. -10 < x < 6 -12 -10 -8
-6
-4
4 4 f. x ≤ _ and x ≥ - _ 5 5
g. x ≥ 8 or x ≤ 1 -2
-1
0
1
2
3
4
9
10
h. no solution i. ⎪t + 333⎥ = 13; min: -346; max: -320 -350
-345
-340
-335
-330
© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.
-325
-320
-315
LSN 17–1
Saxon Algebra 2
Lesson Practice 17
17
b. 160 degrees
3 3 3 _ _ ⎥ = ; 1 inches 1. ⎪t - 1_ 4 8 8
2. When the coordinates are substituted into the formula, the denominator results in a zero; Vertical line. 3. Yes. After isolating the absolute value expression, it is greater than a negative number. Since absolute value is always positive, x can be replaced with any number and the inequality will be true.
c. 240 degrees 11. D 12. a. Pitcher A: 0.2; Pitcher B: 0.25 b. Pitcher B c. Sample: The weather can be a factor in wind resistance. 13.
(2, _43 );
8
y
4 _ 4 2, 3
(
-8
-4
O
) x
4
8
-4 -8
⎡4 -1 ⎤ 8. 3 7 ⎣ 8 -10⎦
14. The polynomials have the same degree, 5. The monomial with greatest degree in the first polynomial is ab4, which has degree 5, and the monomial with greatest degree in the second polynomial is a2b3, which also has degree 5.
9. [2 -16]
15. y = 10
4. infinitely many solutions 5. no solution 6. (1.5, 4.25) 7. B
⎢
2 10. a. k = _ 3 © 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.
16. -6 ≤ x ≤ -1 LSN 17–2
Saxon Algebra 2
Lesson
17
y
17. no solution -8
x
O
-4
18. x = -3 or x = 10
4
8
-4 -8
1 ; The result for 19. x = _ 8 3 is ⎪-6⎥ substituting -_
-12 -16
8
= -6, which is false. 24.
16 ≤ x ≤ 4; 20. -_ 3 -8
-7
-6
-5
-4
-3
-2
-1
0
x 0
2 4
y 5 1
2
3
4
5
6
8 y
21. a.
; x -8
4 -8
-4
6 2
8 1
y
4
8
x
4 3
-4
O
4
8
-4
O
4
8
-8
-8
25. -1005 triangle
26. a. 2 × π × (1.495 × 1011) m = 9.39 × 1011 m = 9.39 × 108 km
b. (6, 8), (10, 2), (-2, -4) ⎪1 1 22. _ 2 2 ⎪1
⎪
23.
1 -4 1
4⎥ -4 = 9 1⎥
⎥
b. 365.25 days × 60 min 60s 24 hr _ ×_ ×_ day
x -3 0 y
3
6
9
hr
min
= 3.156 × 107 s. 9.39 × 108 km __ So, 7
3 -2 -7 -12 -17
3.156 × 10 s
= 29.75 km/s.
© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.
LSN 17–3
Saxon Algebra 2
Lesson
17
27. m = 2; rises 28. 6 cups 29. no variation 30. direct when b and c = 0 or when a and c = 0
© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.
LSN 17–4
Saxon Algebra 2
17
Warm Up 17 1. conjunction 2. -1 ≤ x ≤ 4 3. all real numbers Lesson Practice 17 a. x = 4 or x = -10 -12 -10 -8
-6
-4
-2
0
2
4
6
-2
0
2
4
6
8
5
6
7
8
b. x = 0 or x = 2 c. no solution 1 1 _ or d. x = _ 2 6
e. -10 < x < 6 -12 -10 -8
-6
-4
4 4 f. x ≤ _ and x ≥ - _ 5 5
g. x ≥ 8 or x ≤ 1 -2
-1
0
1
2
3
4
9
10
h. no solution i. ⎪t + 333⎥ = 13; min: -346; max: -320 -350
-345
-340
-335
-330
© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.
-325
-320
-315
LSN 17–1
Saxon Algebra 2
Lesson Practice 17
17
b. 160 degrees
3 3 3 _ _ ⎥ = ; 1 inches 1. ⎪t - 1_ 4 8 8
2. When the coordinates are substituted into the formula, the denominator results in a zero; Vertical line. 3. Yes. After isolating the absolute value expression, it is greater than a negative number. Since absolute value is always positive, x can be replaced with any number and the inequality will be true.
c. 240 degrees 11. D 12. a. Pitcher A: 0.2; Pitcher B: 0.25 b. Pitcher B c. Sample: The weather can be a factor in wind resistance. 13.
(2, _43 );
8
y
4 _ 4 2, 3
(
-8
-4
O
) x
4
8
-4 -8
⎡4 -1 ⎤ 8. 3 7 ⎣ 8 -10⎦
14. The polynomials have the same degree, 5. The monomial with greatest degree in the first polynomial is ab4, which has degree 5, and the monomial with greatest degree in the second polynomial is a2b3, which also has degree 5.
9. [2 -16]
15. y = 10
4. infinitely many solutions 5. no solution 6. (1.5, 4.25) 7. B
⎢
2 10. a. k = _ 3 © 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.
16. -6 ≤ x ≤ -1 LSN 17–2
Saxon Algebra 2
Lesson
17
y
17. no solution -8
x
O
-4
18. x = -3 or x = 10
4
8
-4 -8
1 ; The result for 19. x = _ 8 3 is ⎪-6⎥ substituting -_
-12 -16
8
= -6, which is false. 24.
16 ≤ x ≤ 4; 20. -_ 3 -8
-7
-6
-5
-4
-3
-2
-1
0
x 0
2 4
y 5 1
2
3
4
5
6
8 y
21. a.
; x -8
4 -8
-4
6 2
8 1
y
4
8
x
4 3
-4
O
4
8
-4
O
4
8
-8
-8
25. -1005 triangle
26. a. 2 × π × (1.495 × 1011) m = 9.39 × 1011 m = 9.39 × 108 km
b. (6, 8), (10, 2), (-2, -4) ⎪1 1 22. _ 2 2 ⎪1
⎪
23.
1 -4 1
4⎥ -4 = 9 1⎥
⎥
b. 365.25 days × 60 min 60s 24 hr _ ×_ ×_ day
x -3 0 y
3
6
9
hr
min
= 3.156 × 107 s. 9.39 × 108 km __ So, 7
3 -2 -7 -12 -17
3.156 × 10 s
= 29.75 km/s.
© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.
LSN 17–3
Saxon Algebra 2
Lesson
17
27. m = 2; rises 28. 6 cups 29. no variation 30. direct when b and c = 0 or when a and c = 0
© 2009 Saxon®, an imprint of HMH Supplemental Publishers Inc. All rights reserved.
LSN 17–4
Saxon Algebra 2
