Vectors

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Vectors

A VECTOR? • Describes the motion of an object • A Vector comprises – Direction – Magnitude

Size

• We will consider – Column Vectors – General Vectors – Vector Geometry

Column Vectors Vector a a ~

NOTE! Label is in BOLD.

a

4     2

2 up

4 RIGHT

When handwritten, draw a straight line under the label i.e.

COLUMN Vector

a

Column Vectors Vector b 2 up

b

3 LEFT

 3    2   COLUMN Vector?

Column Vectors Vector u 2 down

n 4 LEFT

 4     2   COLUMN Vector?

Describe these vectors 4   1 1 a   3

b

c

 2    3   d

 4     3  

Alternative labelling B

D

EF

E

AB

F

CD G C

A

GH H

General Vectors A Vector has BOTH a Length & a Direction

All 4 Vectors here are EQUAL in Length and Travel in SAME Direction. All called k

k k k

k k can be in any position

General Vectors Line CD is Parallel to AB

B A

CD is TWICE length of AB

k

D 2k

Line EF is Parallel to AB

E

C

-k F

EF is equal in length to AB EF is opposite direction to AB

Write these Vectors in terms of k B

k

D 2k

½k

1½k

F

G

E A

C

-2k H

Combining Column Vectors B AB

A

k

C AB

D

2 k      1 CB D  32kk A 2 A B  3  2  C D  2 1   1    64  AB C D     32 

Simple combinations C

4 AB    1 BC

   

1    3

   

5  AC =   4 

B A a   b

 c  a  c            d b  d     

Vector Geometry Consider this parallelogram Q

P R

a b

OP  a

 RQ

OR  b

 PQ

Opposite sides are Parallel

OQ  OP  PQ

 a + b

OQ  OR  RQ

 b + a

O

a + b  b + a

OQ is known as the resultant of a and b

Resultant of Two Vectors • Is the same, no matter which route is followed • Use this to find vectors in geometrical figures

Example S is the Midpoint of PQ.

.

Q

S

P

OS  OP  ½ PQ R

a b O

Work out the vector OS

= a + ½b

Alternatively S is the Midpoint of PQ.

.

Q

S

P

OS  OR  RQ  QS

R

a b O

Work out the vector OS

= b + a - ½b = ½b + a = a + ½b

Example C AC= p, AB = q p

A

M

q

Find BC

M is the Midpoint of BC

B

BC = BA + AC = -q + p =p-q

Example C AC= p, AB = q p

A

M

q

Find BM

BM = ½BC

= ½(p – q)

M is the Midpoint of BC

B

Example C AC= p, AB = q p

A

M is the Midpoint of BC

M

q

Find AM

AM = AB

B

+ ½BC

= q + ½(p – q) = q +½p - ½q = ½q +½p

= ½(q + p)

= ½(p + q)

Alternatively C AC= p, AB = q p

A

M is the Midpoint of BC

M

q

Find AM

B

AM = AC + ½CB

= p + ½(q – p) = p +½q - ½p = ½p +½q

= ½(p + q)